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Ilia_Sergeevich [38]
2 years ago
7

Please can someone solve this question ​

Physics
1 answer:
Lorico [155]2 years ago
3 0

Answer:both diagrams are attached.

Explanation:

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a coil of 40 henry inductance is connected in series with aresistance of 8ohm and the combination is joined to the terminals of
Andreyy89

Answer: 5 seconds

Explanation:

Given the following :

Inductance (L) = 40 henry

Resistance = 8 ohms

The circuit given above is a Resistor - Inductor (RL) circuit network. The time constant of an RL circuit is the ratio of the circuit Inductance (L) and Resistance (R). Time constant is measured in seconds.

THAT IS;

Time constant = L / R

THEREFORE ;

Time constant = 40 / 8

Time constant = 5 seconds

7 0
3 years ago
A basketball player passes a ball to a teammate at a velocity of 6 m/s. The ball has a mass of 0.51 kg. If the original player h
Vilka [71]

We can solve the problem by using conservation of momentum.

The player + ball system is an isolated system (there is no net force on it), therefore the total momentum must be conserved. Assuming the player is initially at rest with the ball, the total initial momentum is zero:

p_i = 0

The total final momentum is:

p_f = p_p + p_b

where p_p is the momentum of the player and p_b is the momentum of the ball.

The momentum of the ball is: p_b = mv=(0.51 kg)(6 m/s)=3.06 kg m/s

While the momentum of the player is: p_p = Mv_p, where M=59 kg is the player's mass and vp is his velocity. Since momentum must be conserved,

p_f = p_i = 0

so we can write

p_f = Mv_p + p_b =0

and we find

v_p = -\frac{p_b}{M}=-\frac{3.06 kg m/s}{59 kg}=-0.052 m/s

and the negative sign means that it is in the opposite direction of the ball.

8 0
3 years ago
Read 2 more answers
In a double-slit interference experiment, the wavelength is λ = 432 nm, the slit separation is d = 0.100 mm, and the screen is d
andrew-mc [135]
In the double-slit interference experiment, the distance of the nth-maximum from the center of the screen is given by
y= \frac{n \lambda D}{d}
where
\lambda is the wavelength
D is the distance between the screen and the slits
d is the distance between the slits

In our problem, 
\lambda=432 nm= 432 \cdot 10^{-9} m
D=42.0 cm=0.42 m
d=0.100 mm=0.1 \cdot 10^{-3} m

By applying the previous formula, we can calculate the distance of the 4th maximum from the center of the screen:
y_4 =  \frac{(4)(432 \cdot 10^{-9} m)(0.42 m)}{(0.1 \cdot 10^{-3}m)}=7.25 \cdot 10^{-3} m

Similarly, the distance of the 8th- maximum is
y_8 = \frac{(8)(432 \cdot 10^{-9} m)(0.42 m)}{(0.1 \cdot 10^{-3}m)}=14.5 \cdot 10^{-3} m

Therefore, the distance between the two maxima is
\Delta y=y_8- y_4 = 14.5 \cdot 10^{-3} m- 7.25 \cdot 10^{-3} m =7.25 \cdot 10^{-3} m = 7.25 mm
5 0
3 years ago
Which of the following is equal to the boyant force of a rock placed in a beaker of water?
Elina [12.6K]
B)Weight of displaced fluid
8 0
3 years ago
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An unbalanced force is at work when
kogti [31]
I would go with C because all the rest of the answer are sitting on something.
7 0
3 years ago
Read 2 more answers
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