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snow_tiger [21]
3 years ago
11

What is the LCM of 13/16a^3b^3, 11/30a^5b

Mathematics
1 answer:
vichka [17]3 years ago
8 0

Answer:

The L.C.M of given numbers is \frac{143}{240}a^5b^3.

Step-by-step explanation:

The given expressions are

\frac{13}{16}a^3b^3

\frac{11}{30}a^5b

The factors of given expressions are

\frac{13}{16}a^3b^3=\frac{13}{8}\times \frac{1}{2}\times a\times a\times a\times b\times b\times b

\frac{11}{30}a^5b=\frac{11}{15}\times \frac{1}{2}\times a\times a\times a\times a\times a\times b

L.C.M.=\frac{13}{8}\times \frac{1}{2}\times a\times a\times a\times b\times b\times b\times \frac{11}{15}\times a\times a

L.C.M.=\frac{143}{240}\times a^5\times b^3

L.C.M.=\frac{143}{240}a^5b^3

Therefore, the L.C.M of given numbers is \frac{143}{240}a^5b^3.


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Mode is that number that appears most frequently in the given set of data.

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The Number of pets in Mr. McIntyre’s class ;

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The remaining part of the question is

"Which statement correctly compares the measures of center of the data in the dot plots?

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<h3>What is differentiation?</h3>

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The derivative of the equation is found as;

F(x)=\rm x^{-2} \\\\ F'(x) = nx^{n-1} \\\\ F(x)=\ \rm (x+1)^{-2} \\\\  F'(x)  = -2(x+1)^{-3} \\\\   F'(x)  =\frac{2}{(x+1)^3}

The given function is;

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