A mirror is opaque, meaning that it reflects the light and images that shine on it's reflective surface.
Answer:- 1467 K
Solution:- It asks to calculate the kelvin temperature of the light bulb. Looking at the given info, it is based on ideal gas law equation, PV=nRT.
Given: 
V = 75.0 mL = 0.0750 L
P = 116.8 kPa
We know that, 101.325 kPa = 1 atm
So, 
= 1.15 atm
R is universal gas constant and it's value is
.
T = ?
Let's plug in the values in the equation and solve it for T.

0.08625 = 0.00005878(T)

T = 1467 K
So, the temperature of the light bulb would be 1467 K.
6.02×[10]1 ×64.8=3900.96 moles
A) It becomes a negative ion