Answer:
The dissociation constant of phenol from given information is 
.
Explanation:
The measured pH of the solution = 5.153
Initially c
At eq'm c-x x x
The expression of dissociation constant is given as:
![K_a=\frac{[C_6H_5O^-][H^+]}{[C_6H_5OOH]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BC_6H_5O%5E-%5D%5BH%5E%2B%5D%7D%7B%5BC_6H_5OOH%5D%7D)
Concentration of phenoxide ions and hydrogen ions are equal to x.
![pH=-\log[x]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5Bx%5D)
![5.153=-\log[x]](https://tex.z-dn.net/?f=5.153%3D-%5Clog%5Bx%5D)
The dissociation constant of phenol from given information is .
Answer:
Solution A: crenation
Solution B: hemolysis
Solution C: hemolysis
Solution D: crenation
Solution E: crenation
Explanation:
Hemolysis is the rupturing of red blood cells, which results in the release of hemoglobin (from within the red blood cells) into the plasma. If a red blood cell is placed in a hypotonic solution, water will flow into the cell, the cell will swell and hemolysis will.
Crenation: when a red blood cell is placed in a <em>hypertonic solution (</em>such as highly saline solution), the red blood cell will lose water(osmosis) and will shrink in size. The red blood cell has undergone crenation.
In order for a red blood cell to prevent from undergoing hemolysis or crenation, the cell must be placed in an<em> isotonic solution, </em>i.e either in <u>0.9% (m/v) NaCl solution</u> or <u>5% glucose solution</u>
- Solution B and Solution C are hypotonic solution, thus red blood cell has undergone hemolysis.
- Solution A, D and E are hypertonic solution. thus red blood cell has undergone crenation
Answer:
41 mL
Explanation:
Given data:
Milliliter of HCl required = ?
Molarity of HCl solution = 4.25 M
Mass of CaCO₃ = 8.75 g
Solution:
Chemical equation:
2HCl + CaCO₃ → CaCl₂ + CO₂ + H₂O
Number of moles of CaCO₃:
Number of moles = mass/molar mass
Number of moles = 8.75 g / 100.1 g/mol
Number of moles = 0.087 g /mol
Now we will compare the moles of CaCO₃ with HCl.
CaCO₃ : HCl
1 : 2
0.087 : 2/1×0.087 = 0.174 mol
Volume of HCl:
Molarity = number of moles / volume in L
4.25 M = 0.174 mol / volume in L
Volume in L = 0.174 mol /4.25 M
Volume in L = 0.041 L
Volume in mL:
0.041 L×1000 mL/ 1L
41 mL
Atomic number, because the atomic number is unque to each individua element.
Answer:
b. The molarity of the solution increases
Explanation:
The correct answer is option b, that is the molarity of the solution increases.
Because the molarity is the concentration of the solution and it is explained as the amount of solute in amount of solution.
Solution: is the solute dissolved in solvent.
So if we increases the amount of solute in solvent the concentration in terms of molarity of solution increases and if we increase amount of solvent or water then the concentration or molarity increases.
Suppose we have form a sugar solution of 1 L by adding 4 mole of sugar then what happen
Use the Molarity formula
Molarity = no. of moles / 1 L of solution
put values in the formula
Molarity = 4/ 1 L of solution = 4 M
So the molarity of solution is 4 now if we add 2 mole more sugar to the same amount of sugar and amount of solution remain the same
now the no. of moles of sugar = 6 mole
So,
Use the Molarity formula
Molarity = no. of moles / 1 L of solution
put values in the formula
Molarity = 6 mol / 1 L of solution = 6 M
So the correct option is b.
