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3 years ago

Which electrons participate in chemical bonding?

Chemistry

2 answers:

OverLord2011 [107]3 years ago

7 0

B.) Valence Electrons. The nucleus of the valence electrons attracts and pulls atoms together.

VMariaS [17]3 years ago

4 0

Answer:

Explanation:

I took the test

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Calculate number of grams in 1.15*10^21 molecules of P2O5

Vlada [557]

To go from molecules, we first need to convert to moles and then convert to grams.

To convert from molecules to moles, we need to divide by Avogadro's constant.

1.15*10^21 molecules * (1 mole/6.022*10^23 molecules) = 0.0019097 moles

To convert from moles to grams, we need to use the molar mass.

The molar mass of P₂O₅ is (2*30.98)+(5*16.00) = 141.96
You can find the molar mass using the periodic table.

0.0019097 moles * (141.96 grams/1 mole) = 0.2711 grams.

Since we have 3 significant digits in 1.15*10^21, that means our final answer is limited to 3 significant digits.

Your final answer is 0.271 grams.

6 0

4 years ago

Manganese has a total of 25 electrons, but the following orbital notation for manganese is incorrect. Explain the error in terms

laila [671]

The Orbital configuration for Manganese is as follows:

1s2 2s2 2p6 3s2 3p6 4s2 3d5

It says 3d is shown with five orbitals- this is correct

Then it says the first two orbitals have two electrons-this is incorrect.

When filling in the orbitals for any element, you first need to distribute to ALL orbitals then extras go from there.

The orbital d can have up to 10 electrons so you need to distribute at least one electron to all ten. Since you only have 5 then only 5 orbitals would have electrons in them. In order for ANY of the orbitals to have two electrons, there would need to be AT LEAST 11 electrons to distribute.

4 0

3 years ago

A chemist titrates 110.0 mL of a 0.7684 M methylamine (CH3NH2) sotion with 0.4469 M HNO3 solution at 25 °C. Calculate the pH at

Firdavs [7]

Answer: The pH at equivalence point for the given solution is 5.59.

Explanation:

At the equivalence point,

$n_{HNO_{3}} = n_{CH_{3}NH_{2}}$

So, first we will calculate the moles of $CH_{3}NH_{2}$ as follows.

$n_{CH_{3}NH_{2}} = 0.764 M \times \frac{110 ml}{1000 ml/L}$

= 0.0845 mol

Now, volume of $HNO_{3}$ present will be calculated as follows.

Volume = $\frac{\text{no. of moles}}{\text{Molarity}}$

= $\frac{0.0845}{0.4469 M}$

= 0.1891 L

Therefore, the total volume will be the sum of the given volumes as follows.

110 ml + 189.1 ml

= 299.13 ml

or, = 0.2991 L

Now, $[CH_{3}NH_{3}^{+}] = \frac{0.0845 mol}{0.2991 L}$

= 0.283 M

Chemical equation for this reaction is as follows.

$CH_{3}NH_{3}^{+} + H_{2}O \rightleftharpoons CH_{3}NH_{2} + H_{3}O^{+}$

As, $k_{a} = \frac{k_{w}}{k_{b}}$

= $\frac{10^{-14}}{10^{-3.36}}$

= $2.29 \times 10^{-11}$

Now, $[HNO_{3}] = \sqrt{k_{a}[CH_{3}NH_{3}^{+}]}$

= $\sqrt{2.29 \times 10^{-11} \times 0.283}$

= $2.546 \times 10^{-6}$

Now, pH will be calculated as follows.

pH = $-log [H_{3}O^{+}]$

= $-log (2.546 \times 10^{-6})$

= 5.59

Thus, we can conclude that pH at equivalence point for the given solution is 5.59.

6 0

3 years ago

A student carried out a simple distillation on a compound known to boil at 124 oc and they reported a boiling point of 116-117 o

chubhunter [2.5K]

Answer :

The correct answer is due to incorrect position of thermometer .

Distillation is process of separating two volatile liquids on the basis of their boiling points .In involves the following set up ( shown in image )

Since the Boiling point is found is 116-117 C which is near to 124 C , also the purity was checked and thermometer was calibrated .

So the only error could be possible is position of thermometer .

The position of bulb of thermometer is very important to get an accurate reading of boiling point .The vapor so formed should touch the side walls of bulb as soon as they are formed .

May be the bulb of thermometer was kept far from the vapors formed by liquid so, s<u>ome of the vapor before reaching to bulb start condensing and their Temperature decreases </u>.

Hence , the temperature shown by thermometer was decrease than actual boiling point due to incorrect position of thermometer.

4 0

3 years ago

The OAC simulation showed that warm air over a cold current:

tia_tia [17]

Answer:

received energy from water

4 0

3 years ago