Consider a 400 mL solution of 0.10 M \ce{NaOH}NaOH. Calculate the mass of solid \ce{NaOH}NaOH required to achieve this solution.
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Answer:
Chloride (Cl⁻) and sodium (Na⁺) ions.
Explanation:
Hello,
In this case, since the aqueous species are actually dissociated when reacting and the solid species (ferric carbonate) remains undissolved, we can modify the given reaction as follows:
In such a way, dissociating the aqueous species we obtain:
It means that the net ionic equation is:
Therefore, the spectator ions are those were cancelled out, chloride (Cl⁻) and sodium (Na⁺).
Best regards.