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yan [13]
3 years ago
9

Earth

Chemistry
1 answer:
Juliette [100K]3 years ago
3 0
Full moon I’m pretty sure... good luck!
You might be interested in
Which phrase describes the energy of collision?(1 point)
Kruka [31]

The phrase that describes the energy of collision is D. kinetic energy transferred when billiard balls hit each other.

<h3>What is collision?</h3>

collision can be regarded as  coming together of one solid or direct impact to the other such as car collided with a tree.

Therefore, kinetic energy transferred when billiard balls hit each other is an example.

Learn more about collision at;

brainly.com/question/11352260

8 0
2 years ago
Read 2 more answers
In the formula for the compound XCl4, the X could represent<br> (1) C (3) Mg<br> (2) Η (4) Zn
Anvisha [2.4K]
Correct Answer: option 1 i.e. C

Reason: 
The the compound of interest i.e.  XCl4, since there are 4 Cl atoms bonded to X. This signifies that the valency of X is 4.

There atomic number of C is 6. It's electronic configuration is giving by 1s2 2s2 2p2. Thus, there are 4 electrons in valence shell of C. This signifies that valency of C is 4. Hence the compound present in present case is CCl4.
7 0
3 years ago
Read 2 more answers
The vapor pressure of substance X is 100. mm Hg at 1080.°C. The vapor pressure of substance X increases to 600. mm Hg at 1220.°C
artcher [175]

Explanation:

The given data is as follows.

         P_{1} = 100 mm Hg or \frac{100}{760}atm = 0.13157 atm

         T_{1} = 1080 ^{o}C = (1080 + 273) K = 1357 K

         T_{2} = 1220 ^{o}C = (1220 + 273) K = 1493 K

         P_{2} = 600 mm Hg or \frac{600}{760}atm = 0.7895 atm

          R = 8.314 J/K mol

According to Clasius-Clapeyron equation,

                   log(\frac{P_{2}}{P_{1}}) = \frac{\Delta H_{vap}}{2.303R}[\frac{1}{T_{1}} - \frac{1}{T_{2}}

            log(\frac{0.7895}{0.13157}) = \frac{\Delta H_{vap}}{2.303 \times 8.314 J/mol K}[\frac{1}{1357 K} - \frac{1}{1493 K}]

          log (6) = \frac{\Delta H_{vap}}{19.147}[\frac{(1493 - 1357) K}{1493 K \times 1357 K}]

                0.77815 = \frac{\Delta H_{vap}}{19.147J/K mol} \times 6.713 \times 10^{-5} K

              \Delta H_{vap} = 2.219 \times 10^{5} J/mol

                                   = 2.219 \times 10^{5}J/mol \times 10^{-3}\frac{kJ}{1 J}

                                    = 221.9 kJ/mol

Thus, we can conclude that molar heat of vaporization of substance X is 221.9 kJ/mol.

4 0
3 years ago
Please help me with this
yaroslaw [1]

Answer:

3s orbital

Explanation:

3s is the outermost orbital of magnesium and it loses electron from it, it doesnt even have 4f, 5p or 3d orbitals.

3 0
2 years ago
Read 2 more answers
What is 0.000028474 in scientific notation
antiseptic1488 [7]

Answer:

2.8474 \:  \times  \:  {10}^{ - 5}

this the solution

6 0
3 years ago
Read 2 more answers
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