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r-ruslan [8.4K]
3 years ago
8

Calculate number of g H3PO3 formed from 53.6 g H2O react with excess PCl3?

Chemistry
1 answer:
n200080 [17]3 years ago
3 0
<h3>Answer:</h3>

81.3 g H₃PO₃

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Reaction Molar Ratios
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Unbalanced] PCl₃ + H₂O → HCl + H₃PO₃

↓

[RxN - Balanced] PCl₃ + 3H₂O → 3HCl + H₃PO₃

[Given] 53.6 g H₂O

[Solve] <em>x</em> g H₃PO₃

<u>Step 2: Identify Conversions</u>

[RxN] 3 mol H₂O → 1 mol H₃PO₃

[PT] Molar Mass of H - 1.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

[PT] Molar Mass of P - 30.97 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

Molar Mass of H₃PO₃ - 3(1.01) + 30.97 + 3(16.00) = 82.00 g/mol

<u>Step 3: Stoich</u>

  1. [S - DA] Set up:                                                                                               \displaystyle 53.6 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O})(\frac{1 \ mol \ H_3PO_3}{3 \ mol \ H_2O})(\frac{82.00 \ g \ H_3PO_3}{1 \ mol \ H_3PO_3})
  2. [S - DA] Multiply/Divide [Cancel out unit]:                                                     \displaystyle 81.3023 \ g \ H_3PO_3

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

81.3023 g H₃PO₃ ≈ 81.3 g H₃PO₃

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<u>At the equilibrium: </u>

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