These are the Kepler's laws of planetary motion.
This law relates a planet's orbital period and its average distance to the Sun. - Third law of Kepler.
The orbits of planets are ellipses with the Sun at one focus. - First law of Kepler.
The speed of a planet varies, such that a planet sweeps out an equal area in equal time frames. - Second law of Kepler.
Answer:
Making the lumber thick will make it stiff, which seems good. On the other hand, with thicker lumber, differences in expansion on the two faces have more leverage to make the lumber move.
Answer:
C
Explanation:
Water at normal temperature is a good lubricant and will hinder the brake from working properly when the road is wet. To dry the brakes off, apply brakes gently as you accelerate. This will generate some heat that will evaporate the water with the help of friction.
Answer:
The weight of body is 1.3040 gram.
Explanation:
Given that,
The weight y of a fiddler crab is directly proportional to the 1.25 power of the weight x of its claws.
Suppose a crab with a body weight of 1.8 gram has claws weighing 1.1 gram.
Estimate the weight of a fiddler crab with claws weighing 0.85 gram.
Determine the weight of crab body
We need to calculate the value of proportional constant



Put the value into the formula


We need to calculate the crab weight

Here, x = 0.85 g
Put the value into the formula


Hence, The weight of body is 1.3040 gram.
Answer:
The tension on the clotheslines is 
Explanation:
The diagram illustrating this question is shown on the first uploaded image
From the question we are told that
The distance between the two poles is 
The mass tie to the middle of the clotheslines 
The length at which the clotheslines sags is 
Generally the weight due to gravity at the middle of the clotheslines is mathematically represented as
let the angle which the tension on the clotheslines makes with the horizontal be
which mathematically evaluated using the SOHCAHTOA as follows

=> ![\theta = tan^{-1}[\frac{4}{6} ]](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%20tan%5E%7B-1%7D%5B%5Cfrac%7B4%7D%7B6%7D%20%5D)
=> 
So the vertical component of this tension is mathematically represented a

Now at equilibrium the net horizontal force is zero which implies that

=> 
substituting values

substituting values

