Answer:
Explanation:
500 watts is equivalent to 500J/s
20 minutes is equivalent to 20*60seconds which is 1200 s
330g is equivalent to 330/1000kg which is 0.33kg
The temperature will be (100-23) which is 77°C
The energy will be:
Now we can apply:
Q=*m*ΔT
Q=4.186kJ/kgC * 0.33kg * 77°C
Q=106.37kJ
Energy to boil water is 2260J/kg
2260J/kg*0.33=
so The energy available will be:
=745.8kJ-106.37kJ
=639.43kJ
Now the remaining water will be:
=(1-639.43kJ/745.8kJ)*0.33
Answer:
4.9 eV .
Explanation:
It is the case of discharge through mercury tube light . In it , mercury atoms are exited due to which electrons are sent to higher energy level . Here current drops to zero because electrons are excited to higher level . Energy are absorbed in quantised manner . Energy absorbed by electrons will be 4.9 eV . That means , difference in energy between two energy level is 4.9 eV .
Explanation:
It is given that,
Focal length of the concave mirror, f = -13.5 cm
Image distance, v = -37.5 cm (in front of mirror)
Let u is the object distance. It can be calculated using the mirror's formula as :
u = -21.09 cm
The magnification of the mirror is given by :
m = -1.77
So, the magnification produced by the mirror is (-1.77). Hence, this is the required solution.
A sample of an ideal gas is heated, and its kelvin temperature doubles. The average speed of the molecules in the sample will increases by a factor of
The root-mean square (RMS) velocity is the value of the square root of the sum of the squares of the stacking velocity values divided by the number of values. The RMS velocity is that of a wave through sub-surface layers of different interval velocities along a specific ray path.
Root mean square speed is a statistical measurement of speed.
The root mean square speed can be calculated as : V1 :
if temperature becomes double
let T1 is initial temperature
So , T2 = 2 * T1
now ,
Root mean square speed will be (V2) =
= *
= V1
Thus when temperature becomes double, the root mean square speed increases by a factor of
To learn more about root mean square velocity here
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Answer:
F = 51.3°
Explanation:
The component of weight parallel to the inclined plane must be responsible for the rolling back motion of the car. Hence, the force required to be applied by the child must also be equal to that component of weight:
where,
W = Weight of Wagon = 150 N
θ = Angle of Inclinition = 20°
Therefore,
<u>F = 51.3°</u>