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Vera_Pavlovna [14]
3 years ago
10

Please help me i give 60 point i need help now

Physics
1 answer:
NikAS [45]3 years ago
8 0

Answer:

How many questions should be answered??

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A tennis ball travelling at a speed of 46m/s with a mass of 58kg. Calculate the kinetic<br>energy​
Zanzabum

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its 1/2 the mass of the object times by its velocity ^ 2

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Investigate the relationship between volume and pressure of a gas at a constant temperature.
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Gay Lussac's Law states: At a constant volume Pressure<span> divided by </span>Temperature<span> is</span>constant<span> P/T = k Together these three laws form the foundation of the Ideal </span>Gas<span>Law. Objective: Students will </span>investigate<span> Gay Lussac's Law relating </span>pressure<span> and</span>temperature<span> at a </span><span>constant temperature.</span>
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What causes air to move or circulate from one place to another?
MAXImum [283]

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c

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simple

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How to calculate the slope of position time graph?
Mashcka [7]

Answer:

The slope of a position-time graph can be calculated as:

m=\frac{\Delta y}{\Delta x}

where

\Delta y is the increment in the y-variable

\Delta x is the increment in the x-variable

We can verify that the slope of this graph is actually equal to the velocity. In fact:

\Delta y corresponds to the change in position, so it is the displacement, \Delta s

\Delta x corresponds to the change in time \Delta t, so the time interval

Therefore the slope of the graph is equal to

m=\frac{\Delta s}{\Delta t}

which corresponds to the definition of velocity.

3 0
3 years ago
A satellite moves in a circular orbit at a constant speed v0 around Earth at a distance R from its center. The force exerted on
postnew [5]

Answer:

vT = v0/3

Explanation:

The gravitational force on the satellite with speed v0 at distance R is F = GMm/R². This is also equal to the centripetal force on the satellite F' = m(v0)²/R

Since F = F0 = F'

GMm/R² = m(v0)²/R

GM = (v0)²R  (1)

Also, he gravitational force on the satellite with speed vT at distance 3R is F1 = GMm/(3R)² = GMm/27R². This is also equal to the centripetal force on the satellite at 3R is F" = m(vT)²/3R

Since F1 = F'

GMm/27R² = m(vT)²/3R

GM = 27(vT)²R/3

GM = 9(vT)²R (2)

Equating (1) and (2),

(v0)²R = 9(vT)²R

dividing through by R, we have

9(vT)² = (v0)²

dividing through by 9, we have

(vT)² = (v0)²/9

taking square-root of both sides,

vT = v0/3

6 0
3 years ago
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