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3 years ago

Which line could be added to show the difference a digita leader can make?

1 answer:

8 0

Question: I was honored to be a part of an online group of students from the United States, Africa, and China seeking solutions to water shortages. While we all had great enthusiasm about changing the world, the project quickly dissolved because no one was willing to listen to differing viewpoints.

Which line could be added to show the difference a digital leader can make?

Answer:

The line that can be added to show the difference a digital leader can make is, "We saved the project by allowing each group to share their thoughts and then chose the best solutions"

Explanation:

A digital leader is the one who is innovative, creative, collaborative, experimental, curious and also able to network. The person should have forward thinking capability, most importantly should remain very adaptive, so that can remain relevant to the change. To archive this, he alone can do this. Must have different group of people through which could extract different ideas and views from which he/she could chose the right one for the desired situation.

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Electrons are added into the outermost what in groups 1 & 2

aivan3 [116]

S orbital.

Group 1 elements have a general configuration $ns^{1}$ , where n represents the highest occupied Principal Energy Level. For example, Lithium has the valence configuration $2s^{1}$ whereas Cesium has $6s^{1}$ . Both of them belong to Group 1 of Periodic Table.

Group 2 elements have a general configuration of $ns^{2}$ . For example, Magnesium has $3s^{2}$ as its outer shell configuration while Strontium has the same as $5s^{2}$ .

We see that in both the cases, the outermost S orbital is being filled.

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3 years ago

The mass of a planet is 3.7 x 1024 kg. If the planet has a radius of 9.2 x 106 m what is the acceleration of gravity for a perso

nalin [4]

Explanation:

It s given that,

Mass of a planet, $M=3.7\times 10^{24}\ kg$

Radius of a planet, $R=9.2\times 10^{6}\ m$

(1) We need to find the acceleration due to gravity for a person on the surface of the planet. Its formula is given by :

$g=\dfrac{GM}{R^2}$

$g=\dfrac{6.67\times 10^{-11}\ Nm^2/kg^2\times 3.7\times 10^{24}\ kg}{(9.2\times 10^{6}\ m)^2}$

$g=2.91\ m/s^2$

(2) The escape velocity is given by :

$v=\sqrt{\dfrac{2GM}{R}}$

$v=\sqrt{{\dfrac{2\times 6.67\times 10^{-11}\ Nm^2/kg^2\times 3.7\times 10^{24}\ kg}{9.2\times 10^{6}\ m}}$

v = 7324.61 m/s

Hence, this is the required solution.

3 0

3 years ago

What is the condition for an object experiencing free fall?

S_A_V [24]

Answer:

The body acts under the influence of gravity.

Explanation:

An object experiencing free fall is acting under the influence of gravitational force and the acceleration due gravity is positive for any falling object. The body is able to fall freely due to the effect of gravity on it. This gravity effect causes the body to get attracted to the earth's gravitational surface due to gravitational pull exerted on the body.

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3 years ago

Positive charge Q is placed on a conducting spherical shell with inner radius R1 and outer radius R2. The electric field at a po

gregori [183]

Answer:

E = 0 r <R₁

Explanation:

If we use Gauss's law

Ф = ∫ E. dA = $q_{int}$ / ε₀

in this case the charge is distributed throughout the spherical shell and as we are asked for the field for a radius smaller than the radius of the spherical shell, therefore, THERE ARE NO CHARGES INSIDE this surface.

Consequently by Gauss's law the electric field is ZERO

E = 0 r <R₁

6 0

3 years ago

A bowling ball traveling with constant speed hits the pins at the end of a bowling lane 16.5 m long. The bowler hears the sound

Yakvenalex [24]

Speed = distance/time
= 16.5/2.5 = 6.6 ms^-1

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3 years ago