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3 years ago

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Which line could be added to show the difference a digita leader can make?

1 answer:

tia_tia [17]3 years ago

8 0

Question: I was honored to be a part of an online group of students from the United States, Africa, and China seeking solutions to water shortages. While we all had great enthusiasm about changing the world, the project quickly dissolved because no one was willing to listen to differing viewpoints.

Which line could be added to show the difference a digital leader can make?

Answer:

The line that can be added to show the difference a digital leader can make is, "We saved the project by allowing each group to share their thoughts and then chose the best solutions"

Explanation:

A digital leader is the one who is innovative, creative, collaborative, experimental, curious and also able to network. The person should have forward thinking capability, most importantly should remain very adaptive, so that can remain relevant to the change. To archive this, he alone can do this. Must have different group of people through which could extract different ideas and views from which he/she could chose the right one for the desired situation.

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3 years ago

One form of energy can be _____ another type of energy.

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"One form of energy can be <em>transformed into</em> another type of energy. " <em>(B)</em>

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3 years ago

Consider a car travelling at 60 km/hr. If the radius of a tire is 25 cm, calculate the angular speed of a point on the outer edg

vlabodo [156]

To solve this problem it is necessary to apply the concepts given in the kinematic equations of movement description.

From the perspective of angular movement, we find the relationship with the tangential movement of velocity through

$\omega = \frac{v}{R}$

Where,

$\omega =$ Angular velocity

v = Lineal Velocity

R = Radius

At the same time we know that the acceleration is given as the change of speed in a fraction of the time, that is

$\alpha = \frac{\omega}{t}$

Where

$\alpha =$ Angular acceleration

$\omega =$ Angular velocity

t = Time

Our values are

$v = 60\frac{km}{h} (\frac{1h}{3600s})(\frac{1000m}{1km})$

$v = 16.67m/s$

$r = 0.25m$

$t=6s$

Replacing at the previous equation we have that the angular velocity is

$\omega = \frac{v}{R}$

$\omega = \frac{ 16.67}{0.25}$

$\omega = 66.67rad/s$

Therefore the angular speed of a point on the outer edge of the tires is 66.67rad/s

At the same time the angular acceleration would be

$\alpha = \frac{\omega}{t}$

$\alpha = \frac{66.67}{6}$

$\alpha = 11.11rad/s^2$

Therefore the angular acceleration of a point on the outer edge of the tires is $11.11rad/s^2$

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3 years ago

Which of the following calls one might hear a refree make?

mestny [16]

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Explanation:

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2 years ago

Read 2 more answers

Review Conceptual Example 6 as background for this problem. A car is traveling to the left, which is the negative direction. The

DiKsa [7]

Answer:

(a) 1.21 m/s² (b) 1.75 m/s²

Explanation:

The initial speed of the car, u = 17.8 m/s

Case 1.

Final speed of the car, v = 23.5 m/s

Time, t = 4.68-s

Acceleration = rate of change of velocity

$a=\dfrac{23.5 -17.8 }{4.68}\\\\a=1.21\ m/s^2$

Case 2.

Final speed of the car, v = 15.3 m/s

$a=\dfrac{23.5 -15.3}{4.68}\\\\a=1.75\ m/s^2$

Hence, this is the required solution.

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3 years ago