Answer:
1) 327
2) 3
3) 109
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now I'm not 100% sure #4-6 are correct, but if 4 is right then 5 and 6 are, too.
4) 1074
5) 1074 + 109t
6) 2382
Explanation:
Answer:
- 1.42m/s²
Explanation:
Acceleration is defined as the change in velocity of a body with respect to time.
Acceleration = change in velocity/time
Change in velocity = final velocity - initial velocity
Acceleration = final velocity - initial velocity/time
Since she slows her car from 14.0 to 5.5m/s in 6seconds,
Initial velocity = 14m/s
Final velocity = 5.5m/s
Time = 6seconds
Substituting in the given formula, we will have
Acceleration = 5.5 - 14/6
Acceleration = - 8.5/6
Acceleration = - 1.42m/s²
The negative acceleration shows that the car decelerates.
Answer:
D. 371 N
Explanation:
Friction force equals normal force times the coefficient of friction:
F = Nμ
Since the ground is level, normal force equals weight:
N = mg
Therefore:
F = mgμ
F = (61 kg) (9.8 m/s²) (0.62)
F = 371 N
6^2 + 8^2 = 36 + 64 = 100
sqrt(100) = 10 m/s northwest
Answer:
A) ΔU = 3.9 × 10^(10) J
B) v = 8420.75 m/s
Explanation:
We are given;
Potential Difference; V = 1.3 × 10^(9) V
Charge; Q = 30 C
A) Formula for change in energy of transferred charge is given as;
ΔU = QV
Plugging in the relevant values gives;
ΔU = 30 × 1.3 × 10^(9)
ΔU = 3.9 × 10^(10) J
B) We are told that this energy gotten above is used to accelerate a 1100 kg car from rest.
This means that the initial potential energy will be equal to the final kinetic energy since all the potential energy will be converted to kinetic energy.
Thus;
P.E = K.E
ΔU = ½mv²
Where v is final velocity.
Plugging in the relevant values;
3.9 × 10^(10) = ½ × 1100 × v²
v² = [7.8 × 10^(8)]/11
v² = 70909090.9090909
v = √70909090.9090909
v = 8420.75 m/s
