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Answer:
The mass of the meter stick is
Explanation:
Here since the meter stick is in equilibrium position its net torque and net force should be equal to zero
Since at the begging the meter stick is balanced at center of the meter stick that means its center of mass should be present at
Now lets consider the later case where stick is balanced by two 5.12 g coins .
Here torque due to two coins =
Torque due to weight of meter stick = =
where m = mass of the meter stick
Here .
Upon equating we will be getting mass of the meter stick =