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gtnhenbr [62]
3 years ago
10

What is the justification for each step in solving the inequality?

Mathematics
1 answer:
Troyanec [42]3 years ago
5 0
It is 56



please can i have a brainliest
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HELPPPPP ASAPPPP
KATRIN_1 [288]

Answer:

The maximum height of the volleyball is 12.25 feet.

Step-by-step explanation:

The height of the volleyball, h(t), is modeled by this equation, where t represents the  time, in seconds, after that ball was set :

h(t)=-16t^2+20t+6 ....(1)

The volleyball reaches its maximum height after 0.625 seconds.

For maximum height,

Put \dfrac{dh}{dt}=0

Now put t = 0.625 in equation (1)

h(t)=-16(0.625)^2+20(0.625)+6\\\\h(t)=12.25\ \text{feet}

So, the maximum height of the volleyball is 12.25 feet.

5 0
3 years ago
A rectangle has a length of
Marina CMI [18]

rectangle has a length of

18 feet. The width is x feet

less than the length. If the

area must be less than 216

square feet, what could be

the measurement of the

width?

6 0
2 years ago
The nature park has a pride of 7 adult lions and 4 cubs. The adults eat 6 pounds of meat each day and the cubs eat 3 pounds. Sim
Mademuasel [1]

Answer:

7 x 6 = 42, 42+ 4 x 3, 4 x 3 is 12, 42 + 12 = 54

Step-by-step explanation:

Hope I helped pls give brainliest

8 0
2 years ago
!!!!(Help me please)!!!!
Leona [35]

Answer:

The correct option is C

Step-by-step explanation:

A: We know that the lower quartile is 144, and the upper quartile is 129.5 is you add them all up it is going to equal 273.3. So we know that A can now be crossed out.

B: We know that the lower quartile is 146, and that means the upper quartile is 136.5. So adding all of these numbers up we ill get 282.5 So now <u>B can be crossed out</u>

C: The lower quartile is 114 and the upper quartile is 129.5 and when we add those two numbers up we are going to get 243.5. So we are going to keep this number

D: For the last one we know the lower quartile is 214 and upper is 129.5, and when we add this we get 343.5. So we can cross this out and<u> the only one we have left is going to be C</u>

<u>Hope this help's</u>

3 0
2 years ago
Read 2 more answers
NEED HELP ASAP!!! Please help and I will mark as brainliest!
alex41 [277]
Mnp.............
........
3 0
2 years ago
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