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myrzilka [38]
3 years ago
6

PLEASE HELP AND HURRY

Physics
2 answers:
Ahat [919]3 years ago
6 0

Answer:

B

Explanation:

Vikentia [17]3 years ago
6 0

Answer:

D. m/s^2

Explanation:

meters / second ^2

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PLEASE HELP ME plsss answer this
zlopas [31]
It’s 16.25 meters per second you just add
4 0
3 years ago
I NEED THE RIGHT ANSWER ASAP NO LINKS !!!<br> This is a Science question
sergeinik [125]

Answer:

independent variable

Explanation:

plz mark brainliest

5 0
3 years ago
Read 2 more answers
How does the electron-cloud model describe electrons?
Dominik [7]

Answer:

Yo, you just kind of answered it yourself. The Electron Cloud Model is the informal way of describing an atomic orbital.

Explanation:

The analogy of the cloud of electrons is really describing the groups of electrons orbiting around said atom. Depending on the atom, there will be many or few electrons orbiting around it on all sides which can resemble an all-encompassing cloud.

5 0
3 years ago
A common technique in analysis of scientific data is normalization. The purpose of normalizing data is to eliminate irrelevant c
nataly862011 [7]

Answer:

V₂ = 0.4432

Explanation:

The normalize procedure is widely used in science, in this case we are going to normalize to the voltage value that exists 4 cm away

           Vₙ= V_{measured} / V₀

where the voltage at the desired distance is V₀ = 185 mV = 0.185 V

           

the normalized voltage are

forr x = 4 cm

            V₁ = 185/185

            V₁ = 1

for x = 6.2 cm

             V₂ = 82/185

             V₂ = 0.4432

3 0
3 years ago
Water is flowing through a channel that is 12m wide with a
Alexus [3.1K]

Answer:

Velocity from second channel will be 1.6875 m/sec

Explanation:

We have given width of the channel , that is diameter of the channel 1 d_1 = 12 m

So radius r_1=\frac{d_1}{2}=\frac{12}{2}=6m

Speed through the channel 1 v_1=0.75m/sec

Width , that is diameter of the channel 2 d_2=4m

So r_2=2m

From continuity equation

A_1v_1=A_2v_2

\pi \times 12^2\times 0.75=4\times \pi\times  4^2\times v_2

v_2=1.6875m/sec

So velocity from smaller channel will be 1.6875 m /sec

6 0
3 years ago
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