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ElenaW [278]
3 years ago
5

Consider a nuclear power plant, its transmission lines, and everything it provides energy to as a closed system. Which of the fo

llowing is then true for the system?
thermal energy within system stays constant
mechanical energy within system stays constant
nuclear energy within system stays constant
total energy within system stays constant
Physics
1 answer:
alexandr1967 [171]3 years ago
5 0
I think the correct answer would be <span>total energy within system stays constant. A closed system is a system where there in no mass and energy in and mass and energy out from the system. All of the mass and energy would be constant inside it. Hope this helps.</span>
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1. When the mass of the ice added to the cup increases, the amount of thermal energy needed to change the temperature of the ice
Paha777 [63]

1. When the mass of the ice added to the cup increases, the amount of thermal energy needed to change the temperature of the ice decreases or increases

2. When the students measure the temperature of the water in the cups during the investigation, what is it the students are measuring?

Total kinetic energy of the water

Average kinetic energy of the water

Total amount of heat in the water

3. If the mass of ice added to the cup increases, the total energy in the cup will decrease or increase1. When the mass of the ice added to the cup increases, the amount of thermal energy needed to change the temperature of the ice decreases or increases

2. When the students measure the temperature of the water in the cups during the investigation, what is it the students are measuring?

Total kinetic energy of the water

Average kinetic energy of the water

Total amount of heat in the water

3. If the mass of ice added to the cup increases, the total energy in the cup will decrease or increase1. When the mass of the ice added to the cup increases, the amount of thermal energy needed to change the temperature of the ice decreases or increases

2. When the students measure the temperature of the water in the cups during the investigation, what is it the students are measuring?

Total kinetic energy of the water

Average kinetic energy of the water

Total amount of heat in the water

3. If the mass of ice added to the cup increases, the total energy in the cup will decrease or increase1. When the mass of the ice added to the cup increases, the amount of thermal energy needed to change the temperature of the ice decreases or increases

2. When the students measure the temperature of the water in the cups during the investigation, what is it the students are measuring?

Total kinetic energy of the water

Average kinetic energy of the water

Total amount of heat in the water

3. If the mass of ice added to the cup increases, the total energy in the cup will decrease or increase1. When the mass of the ice added to the cup increases, the amount of thermal energy needed to change the temperature of the ice decreases or increases

2. When the students measure the temperature of the water in the cups during the investigation, what is it the students are measuring?

Total kinetic energy of the water

Average kinetic energy of the water

Total amount of heat in the water

3. If the mass of ice added to the cup increases, the total energy in the cup will decrease or increase

<h2>please mark me as brainliest. ......</h2>

<h2>my friend. ....please help me .....</h2>
3 0
3 years ago
Write a hypothesis for Part II of the lab, which is about the relationship described by F = ma. In the lab, you will use a toy c
Temka [501]

Answer:

F=ma is the relationship where, F is force, m is mass and a is acceleration.

Newton's second law states that  the unbalanced force applied to the object accelerates the object which is directly proportional to the force and inversely to the mass.

If we apply force to a toy car then It will accelerate.

This is how Newton's second law of motion is verified.

6 0
3 years ago
Read 2 more answers
Please help i'm going to throw up from stress
Eddi Din [679]

Answer:

Explanation:

First of all, I used the specific heat of water as 4182 J/(kgC) and the specific heat of ethyl alcohol (EtOH) as 2440 J/(kgC); that means that we need the masses in kg, not g.

120.g = .1200 kg of ethyl alcohol. Now for the formula:

t_f=\frac{(m_{H2O}*spheat_{H2O}*temp_{H2O})+(m_{EtOH}*spheat_{EtOH}*temp_{EtOH})}{(m_{H2O}*spheat_{H2O})+(m_{EtOH}*spheat_{EtOH})} where spheat is specific heat.

Filling that horrifying-looking formula in with some values:

16.0=\frac{(x*4182*20.0)+(.1200*2440*10.0)}{(x*4182)+(.1200*2440)} and

16.0=\frac{83640x+2928}{4182x+292.8} and

16(4182x + 292.8) = 83640x + 2928 and

66912x + 4684.8 = 83640x + 2928 and

1756.8 = 16728x so

x = .105 kg and the amount of water added is 105 g

4 0
3 years ago
A 0.5 kg rock is dropped from a height of 1.0 m above the ground. Approximately how much kinetic energy will be stored in the ro
irina1246 [14]

Answer:

2.45 J

Explanation:

The following data were obtained from the question:

Mass (m) = 0.5 kg

Height (h) = 1 m

Kinetic energy (KE) =?

Next, we shall determine the velocity of the rock after it has fallen half way. This can be obtained as follow:

Initial velocity (u) = 0 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) = 1/2 = 0.5 m

Final velocity (v) =?

v² = u² + 2gh

v² = 0² + (2 × 9.8 × 0.5)

v² = 9.8

Take the square root of both side

v = √9.8

v = 3.13 m/s

Finally, we shall determine the kinetic energy of the rock after it has fallen half way. This can be obtained as follow:

Mass (m) = 0.5 kg

Velocity (v) = 3.13 m/s

Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 0.5 × 3.13²

KE = 0.25 × 9.8

KE = 2.45 J

Therefore, the kinetic energy of the rock after it has fallen half way is 2.45 J

8 0
2 years ago
You stand on top a building 44 m tall with a water balloon. You drop the water balloon from rest. How fast is the balloon moving
Alecsey [184]
<h2>The balloon is moving when it is halfway down the building at 20.78 m/s.</h2>

Explanation:

We have equation of motion v² = u² + 2as

Initial velocity, u = 0 m/s  

Acceleration, a = 9.81 m/s²  

Displacement, s = 0.5 x 44 = 22 m

Substituting  

v² = u² + 2as

v² = 0² + 2 x 9.81 x 22

v² = 431.64

v = 20.78 m/s

Velocity at 22 m = 20.78 m/s

The balloon is moving when it is halfway down the building at 20.78 m/s.

7 0
3 years ago
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