Will give correct answer brainliest

Any object that just fits into your visual field has this angular size. Do all objects that you see this this angular size have

Nataly_w [17]

Answer:

No the angular and linear size will not be same for different objects bearing the same angular size and is dependent on the point of observation. The greater the distance between the observer and the object, the greater the difference between the angular and linear size.

Explanation:

The angular size is the ratio of two lengths namely

$Angular \, Size=\frac{Linear Size}{Distance from the object}$

Here if the distance from the object is unity, the angular and linear size will be similar. However if the distance of observation is very large, the angular size for large bodies with large linear size will be very small.

An example in this regard is Sun.

The linear size of Sun, (the diameter) is 1.3927 million km. Which is very large. However as it is very far from earth, 147.44 million km, the angular size is very small.

it is given as

$Angular \, Size=\frac{1.39}{147.44}=0.009 rad$

Now the same angular size can be of a tennis ball having a diameter of 10 cm , placed at around 10.6 m away.

$Angular \, Size=\frac{0.1}{10.6}=0.009 rad$

3 0

2 years ago

Imagine you are holding a small ball below you so that you look down on its "north pole." turn the ball in a counterclockwise di

enyata [817]

It is rotating Clockwise

8 0

3 years ago

When a circuit is arranged in parallel:

Elenna [48]

Answer:

In a series circuit, all components are connected end-to-end, forming a single path for current flow. In a parallel circuit, all components are connected across each other, forming exactly two sets of electrically common points

7 0

3 years ago

One method of determining the location of the center of gravity of a person is to weigh the person as he/she lies on a board of

andrey2020 [161]

Answer:

x = 1.018 m

Explanation:

given,

height of man = 190 cm

= 1.9 m

scale reading on left = 450 N

scale reading on the right = 390 N

Let center of gravity of man be x distance from feet, feet is on right side.

For system to be in equilibrium moment about center should be equal to zero.

∑M = 0

now,

450(1.9 - x ) - 390 × x = 0

450(1.9 - x ) = 390 × x

855 - 450 x = 390 x

840 x = 855

$x = \dfrac{855}{840}$

x = 1.018 m

hence, point of center of gravity from feet is equal to x = 1.018 m

7 0

3 years ago

What is the difference b/w distance and displacement?

Vlada [557]

Distance is the actual path covered and displacement is the shortest distance from the object to the point of origin.

Please mark as brainliest if satisfied with answer

4 0

3 years ago