1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Musya8 [376]
3 years ago
15

A simple machine that is a straight slanted surface is

Physics
1 answer:
rjkz [21]3 years ago
5 0
Inclined plane is a simple machine that is a straight slanted surface.
You might be interested in
What forces are those that act on an object causing the net force to be something other than zero?
Arisa [49]
Gravity is all ways pulling down and the normal force acting on top of the object and for it to have to push or pull to the object
3 0
3 years ago
I need a short written description of Newton's three laws.
Tom [10]
Newton’s first law of motion, also called the law on inertia, states that an object continues in its state of rest or of uniform motion unless compelled to change that state by an external force.Newton’s second law of motion states that if a net force acts on an object, it will cause an acceleration of that object.Newton’s third law of motion<span> states that for every action there is an equal and opposite reaction. hope this wasnt two long!</span> 
6 0
3 years ago
A 6.0-v battery maintains the electrical potential difference between two parallel metal plates separated by 1.0 mm. what is the
Gnoma [55]
The voltage<span> difference between the two plates can be expressed in terms of the </span>work<span> done on a positive test charge q when it moves from the positive to the negative plate.</span><span>
E=V/d
where V is the voltage and d is the distance between the plates.
 
So,

E=6.0V/1mm= 6000 V/m. The electric field between the plates is 6000 V/m.</span>
5 0
3 years ago
Carol drops a stone in a mine shaft 122.5 metres deep.How
Verizon [17]

Answer:

 T = 5.36 s

Explanation:

given,

depth of the mine shaft = 122.5 m

speed of the sound = 340 m/s

time taken  = ?

time taken by the stone to reach at the bottom

using equation of motion

s = u t + \dfrac{1}{2}gt^2

initial speed , u = 0 m/s

t = \sqrt{\dfrac{2s}{g}}

t = \sqrt{\dfrac{2\times 122.5}{9.8}}

       t = 5 s

time taken by the sound to travel

    d =v x t

 t = \dfrac{d}{v}

 t = \dfrac{122.5}{340}

    t = 0.36 s

total time taken for the sound to reach carol after dropping the stone

T = 5 + 0.36

 T = 5.36 s

7 0
3 years ago
Quando aquecemos água em nossas casas, ao nível do mar, utilizando um recipiente aberto, sua temperatura nunca ultrapassa os 100
iren2701 [21]

Answer:

i dont speak spanish

Explanation:

4 0
3 years ago
Other questions:
  • According to the exercise principle of balance, a workout should __________.
    14·2 answers
  • An unmarked police car traveling a constant 85 km/h is passed by a speeder. Precisely 2.00 s after the speeder passes, the polic
    7·1 answer
  • The energy transfer diagram represents the energy of a person diving into a pool.
    14·2 answers
  • Suppose the initial position of an object is zero, the starting velocity is 3 m/s and the final velocity was 10 m/s. The object
    10·2 answers
  • Determine W (or fuel energy) required to launch a satellite of mass m at rest from a launching pad placed at the surface earth,
    15·1 answer
  • What's the difference in a balanced force in an unbalanced force
    6·1 answer
  • A rock has a mass of 25kg. The acceleration due to gravity is 10m/s and the height of the rock is 42 m. Find the potential energ
    13·2 answers
  • A particle of charge 3.53×10 ​−8 ​​ C experiences a force of magnitude 6.03×10 ​−6 ​​ N when it is placed in a particular point
    11·1 answer
  • A car drives straight down toward the bottom of a valley and up the other side on a road whose bottom has a radius of curvature
    14·1 answer
  • A few alpha particles bounce off a thin sheet of gold foil. What did scientists
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!