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Ghella [55]
3 years ago
11

A 2018 Tesla Model S has a horsepower of 518. How many watts of power does this car model have?

Physics
1 answer:
elena-14-01-66 [18.8K]3 years ago
5 0

Answer:

It depends on the model but these are the watts of each motor

Explanation:

Un motor: 258 HP (262 CV) Dual motor: 154 kW (209 CV) y 197 kW (268 CV). Performance: 154 kW (209 CV) y 225 kW (306 CV).

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The maximum electric field strength in air is 3.0 Mv/m . Stronger electric fields ionize the air and create a spark. What is the
adoni [48]

Answer:

The value is  P_{max} =  2.11 * 10^{6} \  W

Explanation:

From the question we are told that  

    The maximized electric field strength is  E =  3.0 \ MV/m = 3.0 *10^{6} \  V/m

     The diameter is  d =  1.5\ cm  =  0.015 \  m

Generally the cross -sectional area is mathematically represented as

 =>      A =  \frac{\pi * d^2 }{4}

 =>      A =  \frac{3.142  * 0.015^2 }{4}

 =>      A = 0.0001767 \  m^2

Generally the maximum power is mathematically represented as

       P_{max} =  \frac{E_{max}^2}{ 2 * \mu_o * c }  *  A

Here c is the speed of light with value  c =  3.0 *10^{8} \  m/s

        \mu_o is the permeability of free space with value  \mu_o  = 4 \pi *10^{-7} \  H/m

      P_{max} =  \frac{ (3.0 *10^{6})^2}{ 2 * (4 \pi *10^{-7}) * 3.0 *10^{8} }  *   0.0001767

=>   P_{max} =  2.11 * 10^{6} \  W

4 0
3 years ago
A car drives on a circular road of radius R. The distance driven by the car is given by = + [where a and b are constants, and t
pishuonlain [190]

Answer:

The question is incomplete, the complete question is "A car drives on a circular road of radius R. The distance driven by the car is given by d(t)= at^3+bt [where a and b are constants, and t in seconds will give d in meters]. In terms of a, b, and R, and when t = 3 seconds, find an expression for the magnitudes of (i) the tangential acceleration aTAN, and (ii) the radial acceleration aRAD3"

answers:

a.18a m/s^{2}

b. a_{rad}=\frac{(27a +b)^{2}}{R}

Explanation:

First let state the mathematical expression for the tangential acceleration and the radial acceleration.

a. tangential acceleration is express as

a_{tan}=\frac{d|v|}{dt} \\

since the distance is expressed as

d=at^{3}+bt

the derivative is the velocity, hence

V(t)=\frac{dd(t)}{dt}\\V(t)=3at^{2}+b\\

hence when we take the drivative of the velocity we arrive at

a_{tan}=\frac{dv(t)}{dt}\\ a_{tan}=6at\\t=3 \\we have \\a_{tan}=18a m/s^2

b. the expression for the radial acceleration is expressed as

a_{rad}=\frac{v^{2}}{r}\\a_{rad}=\frac{(3at^{2} +b)^{2}}{R}\\t=3\\a_{rad}=\frac{(27a +b)^{2}}{R}

4 0
3 years ago
What are the issues that hinders efforts to achieve sustainability?
Nadya [2.5K]

Answer:

who will solve environmental problems, who is responsible for environmental problems, and who pays the cost of implementing solutions

Explanation:

4 0
3 years ago
21
sergeinik [125]
Distance between the centers of the two objects are the second object
5 0
2 years ago
Question 10 of 15<br> If the period of a wave increases, its frequency must blank
aniked [119]

Answer:

Blank = Increase

4 0
3 years ago
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