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Elan Coil [88]
2 years ago
10

A 0.55 kg projectile is launched from the edge of a cliff with an initial kinetic energy of 1550 J and at its highest point is 1

40 m above the launch point. (a) Calculate the horizontal component of its velocity. (b) Calculate the vertical component of its velocity just after launch. (c) At one instant during its flight the vertical component of its velocity is found to be 65 m/s. At that time, how far is it above or below the launch point
Physics
1 answer:
SCORPION-xisa [38]2 years ago
5 0

Answer:

a). 53.78 m/s

b) 52.38 m/s

c) -75.58 m

Explanation:

See attachment for calculation

In the c part, The negative distance is telling us that the project went below the lunch point.

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Answer:

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Help me, Ive been stuck for 15 minutes
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6 0
3 years ago
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lyudmila [28]

Answer:

The initial energy level = 6

Explanation:

Photon wavelength is proportional to energy. The wavelength of emitted photons is related to the energy levels of the atom as given by the Rydberg formula:

ₕ₁₂

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where n₂ = final energy level = 2

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Rₕ = Rydberg's constant = 1.097 × 10⁷ m⁻¹

λ = wavelength = 410 nm = 410 × 10⁻⁹ m

1/(410 × 10⁻⁹) = (1.097 × 10⁷) [(1/2²) − (1/n₁²)]

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(1/n₁²) = 0.02778

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7 0
3 years ago
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sladkih [1.3K]

Answer:

D

Explanation:

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The correct option is D.

4 0
3 years ago
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