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avanturin [10]
3 years ago
10

3. An airplane is heading north with an airspeed of 325 m/s with a wind from the east at 55.0 m/s. What is the airplane's veloci

ty relative to the ground? Is the airplane's ground speed faster or slowerthan its air speed? Why?​
Physics
1 answer:
liraira [26]3 years ago
3 0

Let <em>a</em> denote the airplane's velocity in the air, <em>g</em> its velocity on the ground, and <em>w</em> the velocity of the wind. (Note that these are vectors.) Then

<em>a</em> = <em>g</em> + <em>w</em>

and we're given

<em>a</em> = (325 m/s) <em>j</em>

<em>w</em> = (55.0 m/s) <em>i</em>

Then

<em>g</em> = - (55.0 m/s) <em>i</em> + (325 m/s) <em>j</em>

The ground speed is the magnitude of this vector:

||<em>g</em>|| = √[ (-55.0 m/s)² + (325 m/s)² ] ≈ 330. m/s

which is faster than the air speed, which is ||<em>a</em>|| = 325 m/s.

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Which feature or process is unique to nuclear power plants when compared to conventional coal-burning power plants?
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Answer:

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Consider a compact car that is being driven
aliina [53]

Answer:

Height h = 37.8 m

Explanation:

Given :

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By using law of conservation of energy ;

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5 0
3 years ago
A Honda Hawk motorcycle and its rider with a combined mass of 450 kg travels around a curve of radius 106 m with a speed of 18 m
umka21 [38]

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F1= uN

F2 = M*(v²/r)

M is the combined mass 450kg

V is the velocity 18m/s

r is the radius 106m

N is the normal reaction 4410N

u is the coefficient of static friction

Making u subject of the formula we have that,

u = {450*(18²/106)} /4410

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A child is sitting on the outer edge of a merry-go-round that is 1.5 m in diameter. If the merry-go-round makes 3.2 rev/min, wha
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we should also know that the circumference of a circle is equal to c = 2pi*r, so each revolution has this length. if the kid does 5.9 revolutions in one minute then the kid spins at v = 5.9*2pi*9m/min

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so your answer will be  5.6 m/s glad i could help!

4 0
2 years ago
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