Explanation:
Hello ! Let's solve this!
1-atomic number: the atomic number is the number of protons that the atom has
2-mass number: is the amount of protons plus the amount of neutrons in the atom
3-atomic weight: average of the masses of an atom per 1/12 of the mass of carbon
4-isotope: it is the same element that has the same number of protons but a different number of neutrons
5-natural abundance: measures the amount of isotopes of an element in nature
6-unit of atomic mass: (uma) is a unit that is equivalent to 1/12 of the carbon atom
Answer:
Explanation:
Given data:
Rotating cylinder length = 9 mi
diameter of cylinder is 5.9 mi
we know that linear acceleration is given as
a = r ω^2
where ω is angular velocity
so
Answer:
0.48 kgm/s
Explanation:
= mass of the particle = 2.43 μg = 2.43 x 10⁻⁶ x 10⁻³ kg = 2.43 x 10⁻⁹ kg
= velocity of the particle = 1.97 x 10⁸ m/s
= momentum of the particle
momentum of the particle is given as
inserting the values
kgm/s
Answer:
2.5 m/s east
Explanation:
Let east be the positive direction for velocity.
The change in momentum of the 0.75 kg model car is ...
m1·v2 -m1·v1 = (0.75 kg)(11 m/s) -(0.75 kg)(-9 m/s)
= (0.75 kg)(20 m/s) = 15 kg·m/s
The change in momentum of the 2.0 kg model car is the opposite of this, so the total change in momentum is zero.
m2·v2 -m2·v1 = (2 kg)(v2 m/s) -(2 kg)(10 m/s) = 2(v2 -10) kg·m/s
The required relation is ...
15 kg·m/s = -2(v2 -10) kg·m/s
-7.5 = v2 -10 . . . . divide by -2
2.5 = v2 . . . . . . . add 10
The velocity of the model truck after the collision is 2.5 m/s east.
Answer:
25 m/s
Explanation:
First of all, we can find the acceleration the object by using Newton's second law of motion:
where
F = 20.0 N is the net force applied on the object
m = 4.0 kg is the mass of the object
a is its acceleration
Solving for a, we find
Now we know that the motion of the object is a uniformly accelerated motion, so we can find its final velocity by using the following suvat equation:
where
v is the final velocity
u = 0 is the initial velocity
is the acceleration
t = 5 s is the time
By substituting,
