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Bumek [7]
4 years ago
14

Sics and Chemistry A (2nd Six Weeks) - SC3200SFA/01

Physics
1 answer:
Andreyy894 years ago
3 0
Force = Mass * Acceleration therefore the red ball with the higher mass will have more force and greater acceleration
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(a) What is the ionization energy of a hydrogen atom that is in the n = 6 excited state? (b) For a hydrogen atom, determine the
crimeas [40]

Answer:

(a) 0.3778 eV

(b) Ratio = 0.0278

Explanation:

The Bohr's formula for the calculation of the energy of the electron in nth orbit is:

E=\frac {-13.6}{n^2}\ eV

(a) The energy of the electron in n= 6 excited state is:

E=\frac {-13.6}{6^2}\ eV

E=-0.3778\ eV

Ionisation energy is the amount of this energy required to remove the electron. Thus, |E| = 0.3778 eV

(b) For first orbit energy is:

E=\frac {-13.6}{1^2}\ eV

E=-13.6\ eV

Ratio=\frac {E_6}{E_1}

Ratio=\frac {-0.3778}{-13.6}

Ratio = 0.0278

7 0
4 years ago
Which statement about thermal energy is true?
NNADVOKAT [17]

Answer:Thermal energy is a measure of a substance 's specific heat

Explanation:

7 0
3 years ago
Read 2 more answers
Using a radar gun, you emit radar waves at a frequency of 6.2 GHz that bounce off of a moving tennis ball and recombine with the
Keith_Richards [23]

Answer:

23.4 m/s

Explanation:

f = actual frequency of the wave = 6.2 x 10⁹ Hz

f_{app} = frequency observed as the ball approach the radar

f_{rec} = frequency observed as the ball recede away from the radar

V = speed of light

v = speed of ball

B = beat frequency = 969 Hz

frequency observed as the ball approach the radar is given as

f_{app}=\frac{f(V+v)}{V}                                 eq-1

frequency observed as the ball recede the radar is given as

f_{rec}=\frac{f(V-v)}{V}                                  eq-2

Beat frequency is given as

B = f_{app} - f_{rec}

Using eq-2 and eq-1

B = \frac{f(V+v)}{V}- \frac{f(V-v)}{V}

inserting the values

969 = \frac{(6.2\times 10^{9})((3\times 10^{8})+v)}{(3\times 10^{8})}- \frac{(6.2\times 10^{9})((3\times 10^{8})-v)}{(3\times 10^{8})}

v = 23.4 m/s

8 0
3 years ago
Photosynthesis transforms molecules of water and carbon dioxide into Molecules of?
brilliants [131]
Into molecules of sugar and oxygen.
The complete reaction of the photosynthesis is in fact:
6CO_2+6H_2O \rightarrow C_6H_{12}O_6+6O_2
and the energy of the light coming from the sun is also used to make the reaction possible.
7 0
4 years ago
With 51 gallons of fuel in its tank, the airplane has a weight of 2390.7 pounds. What is the weight of the plane with 81 gallons
Shtirlitz [24]

Answer: 2561.7 pounds

Explanation:

If we assume the total weight of an airplane (in pounds units) as a <u>linear function</u> of the amount of fuel in its tank (in gallons) and we make a Weight vs amount of fuel graph, which resulting slope is 5.7, we can use the slope equation of the line:

m=\frac{Y-Y_{1}}{X-X_{1}}  (1)

Where:

m=5.7 is the slope of the line

Y_{1}=2390.7pounds is the airplane weight with  51 gallons of fuel in its tank (assuming we chose the Y axis for the airplane weight in the graph)

X_{1}=51gallons is the fuel in airplane's tank for a total weigth of 2390.7 pounds (assuming we chose the X axis for the a,ount of fuel in the tank in the graph)

This means we already have one point of the graph, which coordinate is:

(X_{1},Y_{1})=(51,2390.7)

Rewritting (1):

Y=m(X-X_{1})+Y_{1}  (2)

As Y is a function of X:

Y=f_{(X)}=m(X-X_{1})+Y_{1}  (3)

Substituting the known values:

f_{(X)}=5.7(X-51)+2390.7  (4)

f_{(X)}=5.7X-290.7+2390.7  (5)

f_{(X)}=5.7X+2100  (6)

Now, evaluating this function when X=81 (talking about the 81 gallons of fuel in the tank):

f_{(81)}=5.7(81)+2100  (7)

f_{(81)}=2561.7  (8)   This means the weight of the plane when it has 81 gallons of fuel in its tank is 2561.7 pounds.

3 0
3 years ago
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