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Bumek [7]
4 years ago
14

Sics and Chemistry A (2nd Six Weeks) - SC3200SFA/01

Physics
1 answer:
Andreyy894 years ago
3 0
Force = Mass * Acceleration therefore the red ball with the higher mass will have more force and greater acceleration
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Please helo me to 1st question<br>​
k0ka [10]

Explanation:

6 min in seconds:

6×60

<h2><u>360</u><u> </u><u>s</u><u>e</u><u>c</u><u>o</u><u>n</u><u>d</u><u>s</u><u> </u></h2><h2 /><h2 />

6 min in hours:

<h2><u>0</u><u>.</u><u>1</u><u> </u><u>hours</u></h2>
6 0
3 years ago
A centrifuge in a medical laboratory rotates at an
suter [353]

Answer:

- 273.77 rad/s^2

Explanation:

fo = 3800 rev/min = 3800 / 60 rps = 63.33 rps

f = 0

ωo = 2 π fo = 2 x 3.14 x 63.33 = 397.71 rad/s

ω = 2 π f = 0

θ = 46 revolutions = 46 x 2π radian = 288.88 radian

Let α be the angular acceleration of the centrifuge

Use third equation of motion for rotational motion

\omega^{2}=\omega _{0}^{2}+2\alpha \theta

0^{2}=397.71^{2}+2 \times \alpha \times 288.88

α = - 273.77 rad/s^2

4 0
3 years ago
A potter spins his wheel at 0.98 rev/s. The wheel has a mass of 4.2 kg and a radius of 0.35 m. He drops a chunk of clay of 2.9 k
Bad White [126]

Answer:

v_{f,w} = 1.791\,\frac{m}{s}, v_{f,c} = 0.972\,\frac{m}{s}

Explanation:

The situation can be modelled by applying the Principle of Angular Momentum Conservation:

I_{w} \cdot \omega_{o} = (I_{w} + I_{c})\cdot \omega_{f}

The final angular speed is:

\omega_{f} = \frac{I_{w}}{I_{w}+I_{c}}\cdot \omega_{o}

\omega_{f} = \left(\frac{\frac{1}{2}\cdot (4.2\,kg)\cdot (0.35\,m)^{2} }{\frac{1}{2}\cdot (4.2\,kg)\cdot (0.35\,m)^{2} + \frac{1}{2}\cdot (2.9\,kg)\cdot (0.19\,m)^{2}}\right)\cdot (0.98\,\frac{rev}{s} )\cdot \left(\frac{2\pi\,rad}{1\,rev}  \right)

\omega_{f} \approx 5.116\,\frac{rad}{s}

The tangential velocities of the wheel and the clay are, respectively:

v_{f, w} = (0.35\,m)\cdot (5.116\,\frac{rad}{s} )

v_{f,w} = 1.791\,\frac{m}{s}

v_{f, c} = (0.19\,m) \cdot (5.116\,\frac{rad}{s} )

v_{f,c} = 0.972\,\frac{m}{s}

5 0
3 years ago
A piano string having a mass per unit length equal to 5.00× 10⁻³kg / m is under a tension of 1350N . Find the speed with which a
DiKsa [7]

Based on the mass per unit length and the tension, the speed that the wave travels on this string is 519.615 m/s.

<h3>What is the speed?</h3><h3 />

The speed that the wave travels can be found as:

Velocity² = Tension / Mass per length

Solving gives:

Velocity² = 1,350 / 0.005

Velocity² = 270,000

Velocity = √270,000

= 519.615 m/s

Find out more on the speed of a wave at brainly.com/question/12215474

#SPJ4

8 0
2 years ago
In the United States, when we use this non–renewable resource to generate power, the environment is harmed.
ikadub [295]
Coal, natural gas, and petroleum all qualify as correct answers.
7 0
4 years ago
Read 2 more answers
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