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r-ruslan [8.4K]
3 years ago
13

!LOOK AT THE PICTURE!Simplify 15.6 divided by negative 3

Mathematics
1 answer:
muminat3 years ago
3 0

Answer:

c -5.2 tell me if you need the explanation

Step-by-step explanation:

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I want to say the answer is D

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Step-by-step explanation:

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3 years ago
Using the drawing, if the measure of angle 2 is 42 and the measure of angle 3 is 52, what is the measure of angle 6
AleksandrR [38]

(2x10) +22=42

(3x10) +22=52

(6x10) +22=82



Step-by-step explanation:


3 0
3 years ago
Factor the following binomial: 14a^4b^3c + 18a^2b
Alla [95]

Answer:

2 a^2 b (7 a^2 b^2 c + 9)

Step-by-step explanation:

Factor the following:

14 a^4 b^3 c + 18 a^2 b

Hint: | Factor common terms out of 14 a^4 b^3 c + 18 a^2 b.

Factor 2 a^2 b out of 14 a^4 b^3 c + 18 a^2 b:

Answer: 2 a^2 b (7 a^2 b^2 c + 9)

8 0
3 years ago
A firm wanted to see if there was a significant difference between two neighboring communities in terms of their usage of social
luda_lava [24]

Answer:

There is no difference between two neighboring communities in terms of their usage of social media.

Step-by-step explanation:

In this case we need to determine whether there is any difference between two neighboring communities in terms of their usage of social media.

The hypothesis can be defined as follows:  

<em>H₀</em>: There is no difference between two neighboring communities in terms of their usage of social media, i.e. <em>p</em>₁ - <em>p</em>₂ = 0.  

<em>Hₐ</em>: There is a significant difference between two neighboring communities in terms of their usage of social media, i.e. <em>p</em>₁ - <em>p</em>₂ ≠ 0.  

The test statistic is defined as follows:

 z=\frac{\hat p_{1}-\hat p_{2}}{\sqrt{\hat P(1-\hat P)[\frac{1}{n_{1}}+\frac{1}{n_{2}}]}}

The information provided is:

n₁ = 150

n₂ = 200

\hat p_{1} = 0.55

\hat p_{2}=\frac{120}{200}=0.60

Compute the total proportions as follows:

 \hat P=\frac{n_{1}\hat p_{1}+n_{2}\hat p_{2}}{n_{1}+n_{2}}=\frac{(150\times 0.55)+(200\times 0.60)}{150+200}=0.579

Compute the test statistic value as follows:

 z=\frac{\hat p_{1}-\hat p_{2}}{\sqrt{\hat P(1-\hat P)[\frac{1}{n_{1}}+\frac{1}{n_{2}}]}}

    =\frac{0.55-0.60}{\sqrt{0.579(1-0.579)[\frac{1}{150}+\frac{1}{200}]}}\\\\=-0.94

The test statistic value is -0.94.

The decision rule is:

The null hypothesis will be rejected if the <em>p</em>-value of the test is less than the significance level, <em>α</em> = 0.01.  

Compute the <em>p</em>-value as follows:

 p-value=2\times P(Z

*Use a <em>z</em>-table.

The <em>p</em>-value of the test is 0.35.

<em>p</em>-value = 0.35 > <em>α</em> = 0.01.  

The null hypothesis will not be rejected at 1% significance level.

Thus, it can be concluded that there is no difference between two neighboring communities in terms of their usage of social media.

8 0
3 years ago
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