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r-ruslan [8.4K]
3 years ago
13

!LOOK AT THE PICTURE!Simplify 15.6 divided by negative 3

Mathematics
1 answer:
muminat3 years ago
3 0

Answer:

c -5.2 tell me if you need the explanation

Step-by-step explanation:

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A solid has 16 faces and 14 vertices. How many edges does the solid have
PSYCHO15rus [73]
We know the number of faces and vertices of the solid and we have to calculate the number of edges.We have : F = 16 and V = 14.The formula is:F - E + V = 216 - E + 14 = 216 + 14 - 2 = EE = 30 - 2E = 28Answer: The solid has 28 edges.

4 0
3 years ago
8z-13=7 what's the number that replaces z
Goshia [24]
All you do is solve for z. So 8z-13=7. To solve for a variable you have to do the opposite to cancel out the numbers on each side. First you add 13 over to 7 to cancel out 13 on the z side. So 8z=20 is what you have left. Then you divide 8 on both sides to cancel out 8 on the z side. what you are left with is z=2.5. Lastly you plug and check. 8(2.5) - 13 = 7, 20-13=7. And thats correct so z is 2.5.
4 0
3 years ago
Read 2 more answers
write an equation to solve for x your only writing the equation. 7x+9 5×+3 there's three answers the bottom one is if none of th
professor190 [17]

Answer:

<h2>7x + 9 + 5x + 3 = 180</h2>

Step-by-step explanation:

its a supplementary angles:

so the equation is add the two equation equals to 180

7x + 9 + 5x + 3 = 180

3 0
3 years ago
NOWWWWWWWWWWWWWWWWWWWWWWWWWWWW
Anon25 [30]

Answer: 46 degrees

Step-by-step explanation:

180-134=46 degrees to solve for x

3 0
2 years ago
You are given the parametric equations x=2cos(θ),y=sin(2θ). (a) List all of the points (x,y) where the tangent line is horizonta
vladimir1956 [14]

Answer:

The solutions listed from the smallest to the greatest are:

x:  -\sqrt{2}   -\sqrt{2}  \sqrt{2}  \sqrt{2}

y:      -1         1     -1     1

Step-by-step explanation:

The slope of the tangent line at a point of the curve is:

m = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }

m = -\frac{\cos 2\theta}{\sin \theta}

The tangent line is horizontal when m = 0. Then:

\cos 2\theta = 0

2\theta = \cos^{-1}0

\theta = \frac{1}{2}\cdot \cos^{-1} 0

\theta = \frac{1}{2}\cdot \left(\frac{\pi}{2}+i\cdot \pi \right), for all i \in \mathbb{N}_{O}

\theta = \frac{\pi}{4} + i\cdot \frac{\pi}{2}, for all i \in \mathbb{N}_{O}

The first four solutions are:

x:   \sqrt{2}   -\sqrt{2}  -\sqrt{2}  \sqrt{2}

y:     1        -1        1     -1

The solutions listed from the smallest to the greatest are:

x:  -\sqrt{2}   -\sqrt{2}  \sqrt{2}  \sqrt{2}

y:      -1         1     -1     1

6 0
2 years ago
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