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Tanzania [10]
3 years ago
13

A Formula One race car with mass 760.0 kg is speeding through a course in Monaco and enters counterclockwise direction about the

origin of the circle. At another part of the course, the car enters a second circular turn at 170.0 km/h also in the counterclockwise direction. If the radius of curvature of the first turn is 125.0 m and that of the second is 100.0 m, compare the angular momenta of the race car in each turn taken about the origin of the circular turn. (Compare using the magnitudes of the angular momenta for each turn.)
Physics
1 answer:
weeeeeb [17]3 years ago
4 0

Answer:

g

Explanation:

gg

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A neutral atom possesses an atomic number of 13 and an atomic mass of 27. Three electrons are lost. From what region of the atom
slega [8]
The atomic number of the atom is 13. This means that its electronic configuration is (2 8 3) or in other words:
1<span>s2, </span>2<span>s2, </span>2<span>p6, </span>3<span>s2, </span>3<span>p<span>1

If three electrons are lost, then these electrons are removed from the outermost level.
In our case, electrons are removed from the third energy level (one electron is removed from the 3p orbital and two electrons are removed from the 3s orbital).</span></span>
8 0
3 years ago
Which title goes with this list: Amendments Articles Preamble?
anastassius [24]
D. City and U.S. Government, but I’m not sure what the context is though.
8 0
3 years ago
I neeed help im so comfused Points Possible: 1, Points Correct: 0 Which group of numbers is listed from greatest to least? -3, -
Alona [7]

The groups aren't well formatted ;

The groups are ;

(-3, -1, 0, 2, 7) ; (9, 7, 6, -5, -4) ; (8, -6, 5, -4, 1) ; (-3, -4, -7, -8, -9)

Answer:

(-3, -4, -7, -8, -9)

Explanation:

Given the following group of numbers :

Evaluating each group of values for which is correctly arranged from greatest to least.

(-3, -1, 0, 2, 7) : - 1 is greater than - 3 (the group isn't arranged from greatest to least)

(9, 7, 6, -5, -4) : - 4 is greater than - 5 ; hence, the group isn't arranged from greatest to least

(8, -6, 5, -4, 1) : 5 is greater than - 6 ; hence, the group isn't arranged from greatest to least

(-3, -4, -7, -8, -9) ; the group of numbers here is arranged from greatest to least ;

(-3 > -4 > -7 > -8 > -9) ; hence, the correct group

5 0
3 years ago
d) Provided a recording medium (film) with sensitivity of 100uJ/cm2 and a power detector with 10mm of diameter, background measu
lara31 [8.8K]
We are given with:
Sensitivity: 100uJ/cm2
Diameter: 10mm
Background Optical Power: 8uW
Source Optical Power: 50uW

Required: exposure time

Solution:
Exposure time =  sensitivity x area / (background power - source power)
= 100uJ/cm2 (π/4) (1 cm)² / (80 uW - 50 uW)
= 2.62 s

The exposure time is 2.62 seconds.
3 0
3 years ago
Review Conceptual Example 16 as background for this problem. The water skier there has a mass of 73 kg. Find the magnitude of th
Slav-nsk [51]

Answer:

a) F = 100.375 N

b) F = 38.252 N

Explanation:

a) she is accelerated from rest to a speed of 11 m/s in 8.0 s

We get the acceleration we use this equation,

v = u + at

where v is the final velocity - 11 m/s

u = initial velocity = 0 m/s (from rest)

t is time taken = 8 s

Since v = u + at  

11 = 0 + a×8

8a = 11

a = 11/8 = 1.375

a = 1.375 m/s²

The force equation is given by:

F = ma

F is the force, m is mass = 73 kg and a is acceleration

F = 73 × 1.375 = 100.375

F = 100.375 N

(b) she lets go of the tow rope and glides to a halt in 21 s.

We get the acceleration we use this equation,

v = u + at

where v is the final velocity = 0 m/s (to a halt)

u = initial velocity = 11 m/s

t is time taken = 21 s

Since v = u + at  

0 = 11 + a×21

21a = -11

a = -11/21 = -0.524

a = 0.524 m/s²

The force equation is given by:

F = ma

F is the force, m is mass = 73 kg and a is acceleration

F = 73 × 0.524 = 38.252

F = 38.252 N

6 0
3 years ago
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