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Tanzania [10]
3 years ago
13

A Formula One race car with mass 760.0 kg is speeding through a course in Monaco and enters counterclockwise direction about the

origin of the circle. At another part of the course, the car enters a second circular turn at 170.0 km/h also in the counterclockwise direction. If the radius of curvature of the first turn is 125.0 m and that of the second is 100.0 m, compare the angular momenta of the race car in each turn taken about the origin of the circular turn. (Compare using the magnitudes of the angular momenta for each turn.)
Physics
1 answer:
weeeeeb [17]3 years ago
4 0

Answer:

g

Explanation:

gg

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Describe a change caused by kinetic energy as well as a change that involves potential energy
kykrilka [37]
Kinetic energy is formed when the object is in motion.
Potential energy is the energy that is formed relative to others.

One of the example is Corn flour factory.

Corn turned into flour by a windmill that moved by the waterfall. Movement of the mill is relative to the power given by waterfall (potential energy) and the spinning crushes the corn into flour (kinetic energy)
5 0
3 years ago
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a cone is constructed by cutting a sector from a circular sheet of metal with radius . the cut sheet is then folded up and welde
Svet_ta [14]

The expression for the radius and height of the cone can be obtained from

the property of a function at the maximum point.

  • The \ radius, \ of \ the \ base \ of \ the \ cone \ is \ \sqrt{ \dfrac{3}{4}} \times radius \ of \ circular \ sheet \ metal
  • The height of the cone is half the length of the radius of the circular sheet metal.

Reasons:

The part used to form the cone = A sector of a circle

The length of the arc of the sector = The perimeter of the circle formed by the base of the cone.

Volume \ of \ a \ cone = \dfrac{1}{3} \cdot  \pi \cdot r^3 \cdot h

  • Volume \ of \ a \ cone, \, V = \dfrac{1}{3} \cdot  \pi \cdot r^3 \cdot \sqrt{(s^2- r^2)}

θ/360·2·π·s = 2·π·r

Where;

s = The radius of he circular sheet metal

h = s² - r²

  • \dfrac{dV}{dr} = \dfrac{d}{dr}  \left(\dfrac{1}{3} \cdot  \pi \cdot r^3 \cdot \sqrt{(s^2- r^2)}\right) = \dfrac{\pi \cdot (3 \cdot r^2 \cdot  s^2 - 4 \cdot r^4)}{\sqrt{(s^2- r^2)}} = 0

3·r²·s² - 4·r⁴ = 0

3·r²·s² = 4·r⁴

3·s² = 4·r²

\underline{\left  \right. The \ radius, \, r =\sqrt{ \dfrac{3}{4}} \cdot s}

\underline{The \ height, \, h =\sqrt{s^2 - \dfrac{3}{4}\cdot s^2} = \dfrac{s}{2}}}

Learn more here:

brainly.com/question/14466080

3 0
2 years ago
Here is a graph of speed vs time. If the object is moving to the east, which BEST describes the speed and velocity of the graph?
san4es73 [151]

Answer: A JUST DID IT ON USA TESTPREP

Explanation:

5 0
3 years ago
g An airplane is flying through a thundercloud at a height of 1500 m. (This is a very dangerous thing to do because of updrafts,
Stolb23 [73]

Answer:

523269.9\ \text{N/m}

Explanation:

q = Charge

r = Distance

q_1=25\ \text{C}

r_1=3000\ \text{m}

q_2=40\ \text{C}

r_2=850\ \text{m}

The electric field is given by

E=E_1+E_1\\\Rightarrow E=k(\dfrac{q_1}{r_1^2}+\dfrac{q_2}{r_2^2})\\\Rightarrow E=9\times 10^9\times (\dfrac{25}{3000^2}+\dfrac{40}{850^2})\\\Rightarrow E=523269.9\ \text{N/m}

The electric field at the aircraft is 523269.9\ \text{N/m}

4 0
3 years ago
A nitrogen isotope has an atomic number of 7 and an atomic mass of 15. the respective numbers of neutrons, protons, and electron
anygoal [31]
Atomic Number = amount of protons. Atomic mass = protons (7) and neutrons (8)


Electrons will be the protons - any charge the isotope has. For example, a +2 charge would make the electrons 7- (+2) = 5. A -2 charge would be electrons 7 - (-2) = 9
6 0
3 years ago
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