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Tanzania [10]
3 years ago
13

A Formula One race car with mass 760.0 kg is speeding through a course in Monaco and enters counterclockwise direction about the

origin of the circle. At another part of the course, the car enters a second circular turn at 170.0 km/h also in the counterclockwise direction. If the radius of curvature of the first turn is 125.0 m and that of the second is 100.0 m, compare the angular momenta of the race car in each turn taken about the origin of the circular turn. (Compare using the magnitudes of the angular momenta for each turn.)
Physics
1 answer:
weeeeeb [17]3 years ago
4 0

Answer:

g

Explanation:

gg

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Which two factors affect the size of the gravitational field?
aliina [53]

Answer:

Explanation:

mass and distance

8 0
3 years ago
During which period did the first large herbivores and carnivores appear?
natali 33 [55]
The first large herbivores and carnivores appeared during the Mesozoic Era, which is divided into three periods-- Triassic, Jurassic and Cretaceous. The herbivores and and carnivores increased in size during the Jurassic Period. And some of the largest dinosaurs emerged during this period as well.
7 0
4 years ago
Shanai drove 40 miles to the west, then turned around and drove 70 miles to the east. Draw vectors that show each segment of her
Dmitry [639]
Well she drove 30 more miles to the east than the west but I don’t understand what u are asking
4 0
3 years ago
WILL GIVE BRAINLIEST!!!
kumpel [21]

Answer:

72.53 mi/hr

Explanation:

From the question given above, the following data were obtained:

Vertical distance i.e Height (h) = 8.26 m

Horizontal distance (s) = 42.1 m

Horizontal velocity (u) =?

Next, we shall determine the time taken for the car to get to the ground.

This can be obtained as follow:

Height (h) = 8.26 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

8.26 = ½ × 9.8 × t²

8.26 = 4.9 × t²

Divide both side by 4.9

t² = 8.26 / 4.9

Take the square root of both side by

t = √(8.26 / 4.9)

t = 1.3 s

Next, we shall determine the horizontal velocity of the car. This can be obtained as follow:

Horizontal distance (s) = 42.1 m

Time (t) = 1.3 s

Horizontal velocity (u) =?

s = ut

42.1 = u × 1.3

Divide both side by 1.3

u = 42.1 / 1.3

u = 32.38 m/s

Finally, we shall convert 32.38 m/s to miles per hour (mi/hr). This can be obtained as follow:

1 m/s = 2.24 mi/hr

Therefore,

32.38 m/s = 32.38 m/s × 2.24 mi/hr / 1 m/s

32.38 m/s = 72.53 mi/hr

Thus, the car was moving at a speed of

72.53 mi/hr.

7 0
3 years ago
Determine the kinetic of 600 kg roller coaster car that is moving with the speed of 35.2 m/s.
antiseptic1488 [7]
The answer is 10,560 Joules or 1.1*10^4


Explanation:

Step 1: Calculate
The equation for Kinetic Energy is

Kinetic energy=.5 times Mass times Velocity²
KE=.5*m*v²

so we plug in our numbers
KE=.5*600*35.2²

This works out to be 10,560 Joules or 1.1*10^4
5 0
3 years ago
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