The formula C2H4 can be classified as
2 answers:
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The question is incorrect, nitration of methylbenzoate occurs at 3 position to get, methyl 3-nitrobenzoate.
This is because, in present reaction the reactant i.e. methylbenzoate, has low electron density at m-position.
Due to this, NO2+ prefentially attaches m-position to form methyl 3-nitro benzoate as the product.
A detailed reaction mechanism for formation of product is provided below.
This is because, in present reaction the reactant i.e. methylbenzoate, has low electron density at m-position.
Due to this, NO2+ prefentially attaches m-position to form methyl 3-nitro benzoate as the product.
A detailed reaction mechanism for formation of product is provided below.
Answer : The metal used was iron (the specific heat capacity is ).
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
where,
= specific heat of unknown metal = ?
= specific heat of water =
= mass of unknown metal = 150 g
= mass of water = 200 g
= final temperature of water =
= initial temperature of unknown metal =
= initial temperature of water =
Now put all the given values in the above formula, we get
Form the value of specific heat of unknown metal, we conclude that the metal used in this was iron (Fe).
Therefore, the metal used was iron (the specific heat capacity is ).