Main Answer: The standard electrode potential of galvanic cell constructed from barium and manganese electrode is 4.097.
Explanation:
When the galvanic cell constructed between Manganese and Barium, the half reactions will be as follows:
Mn2+(aq) + 2e-⟶ Mn(s) E1 = −1.185
Ba2+(aq) + 2e-⟶ Ba(s) E2 = −2.912
By considering the above two reactions, the standard electrode potential can be calculated.
The galvanic cell standard electrode potential is given by E1 + E2 = 1.185 + 2.912 = 4.097 volts
What is standard electrode potential?
Standard electrode potential is defined as the measure of reducing power of any compound or element. Its units are volts.
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Answer:
1) SO₄
²⁻ : (+6)
H₂S : (-2)
Explanation:
a) <u>Sulfate reducers</u> are widespread in muds and other sediments, water-logged soils, etc., environments that contain SO₄ ²⁻ and become anoxic as a result of microbial decomposition.
Sulfate (SO₄ ²⁻), the most oxidized form of sulfur (+6), <u>is reduced</u> by these
sulfate-reducing bacteria. The end product of sulfate reduction is hydrogen sulfide, H₂S, (oxidation number -2) an important natural product that participates in many biogeochemical processes. The H₂S they generate is responsible for the pungent smell (like that of rotten eggs) often encountered near coastal ecosystems. When sulfate-reducing bacteria grow, the H₂S formed from SO₄ ²⁻ reduction combines with the ferrous iron to form black, insoluble ferrous sulfide, which is not toxic. This is important for the conservation of the environment.
b) The net ionic equation under acidic conditions is:
4 H₂ + SO₄²⁻ + H⁺ → HS⁻ + 4 H₂O
Global reaction: SO₄²⁻ + 2H⁺ → H₂S + O₂
Answer: (3) The difference in electronegativity between carbon and oxygen is greater than that between fluorine and oxygen.
Explanation: Polarity of a molecule is due to the difference in electronegativity of the atoms. More is the electronegativity difference, more is the polarity.
Electronegativity of carbon = 2.5
Electronegativity of oxygen = 3.5
Electronegativity of fluorine = 4.0
Thus the difference in electronegativity of carbon and oxygen is=(3.5-2.5)= 1.0
Thus the difference in electronegativity of fluorine and oxygen is=(4.0-3.5)= 0.5.
Thus C-O bond is more polar than F-O bond.
The answer is D. Use the equation PV=nRT
P=(.567mol)(.0821)(300K)/4.5L
