Answer:
i) 0,7 molH20/s
ii)11,2 g O/s
iii)1,4 g H/s
Explanation:
i) To find the molar flow rate of water, we just convert the mass of water to moles of water using its molecular weight(g/mol) and changing to the proper units (lb to grames and hours to seconds):
ii) Now we just consider the oxygen in the water stream (for 1 mole of water there is 1 mole of oxygen):
iii)Just considering the hydrogen in the stream (for 1 mole of water there is 2 moles of hydrogen):
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Answer:
9.4 liter
Explanation:
1) Data:
V₁ = 10.0 L
T₁ = 25°C = 25 + 273.15 K = 298.15 K
P₁ = 98.7 Kpa
T₂ = 20°C = 20 + 273.15 K = 293.15 K
P₂ = 102.7 KPa
V₂ = ?
2) Formula:
Used combined law of gases:
PV / T = constant
P₁V₁ / T₁ = P₂V₂ / T₂
3) Solution:
Solve the equation for V₂:
V₂ = P₁V₁ T₂ / (P₂ T₁)
Substitute and compuite:
V₂ = P₁V₁ T₂ / (P₂ T₁)
V₂ = 98.7 KPa × 10.0 L × 293.15 K / (102.7 KPa × 298.15 K)
V₂ = 9.4 liter ← answer
You can learn more about gas law problems reading this other answer on
Explanation:
