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Murrr4er [49]
3 years ago
14

What’s the density of a fluid if a 5.00 ml of urine sample from a patient suffering from symptoms resembling those of diabetes m

ellitus.The mass of the urine sample is 5.025g
Chemistry
1 answer:
tankabanditka [31]3 years ago
5 0

Answer:

1.005g/ml or 1.01 (round up)

Explanation:

The formula for density is mass/volume.

So for this problem Density= 5.025g/5.00ml--------> 1.005g/ml

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Answer:

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<u>Answer:</u> The mass of precipitate (lead (II) iodide) that will form is 119.89 grams

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To calculate the number of moles for given molarity, we use the equation:

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The balanced chemical equation for the reaction of lead chlorate and sodium iodide follows:

Pb(ClO_3)_2(aq.)+2NaI(aq.)\rightarrow PbI_2(s)+2NaClO_3(aq.)

The precipitate (insoluble salt) formed is lead (II) iodide

By Stoichiometry of the reaction:

2 moles of NaI produces 1 mole of lead (II) iodide

So, 0.52 moles of NaI will produce = \frac{1}{2}\times 0.52=0.26mol of lead (II) iodide

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

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Putting values in above equation, we get:

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Hence, the mass of precipitate (lead (II) iodide) that will form is 119.89 grams

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