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alisha [4.7K]
3 years ago
9

Which has more mass, one mole of carbon (C) or one mole of copper (Cu)? Explain.

Chemistry
2 answers:
inysia [295]3 years ago
6 0
Carbon — pay attention to your periodic table trends
dedylja [7]3 years ago
3 0
Carbon.
You’re welcome
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Which atom is more reactive,sodium or sulfur, why
Leto [7]

Answer:

Sodium is more reactive than sulfur.

Valency of Sodium is 1.

Valency of Sulfur is 2.

(Valency is the number of electrons in the outermost orbit of an atom which can be taken, given out or shared by an atom.)

4 0
3 years ago
2 points
777dan777 [17]

Answer:

glucose and oxygen

Explanation:

Glucose and oxygen are needed for cellular respiration to occur:)

4 0
3 years ago
Water flows more easily than syrup, which means water has
-BARSIC- [3]

Answer:

lower viscosity than syrup

4 0
3 years ago
Read 2 more answers
A certain amount of H2S was added to a 2.0 L flask and allowed to come to equilibrium. At equilibrium, 0.072 mol of H2 was found
SIZIF [17.4K]

Answer:

0.098 moles H₂S

Explanation:

The reaction that takes place is

  • 2H₂(g) + S₂(g) ⇄ 2H₂S(g)  keq = 7.5

We can express the equilibrium constant as:

  • keq = [H₂S]² / [S₂] [H₂]² = 7.5

With the volume we can <u>calculate the equilibrium concentration of H₂</u>:

  • [H₂] = 0.072 mol / 2.0 L = 0.036 M

<em>The stoichiometric ratio</em> tells us that <u>the concentration of S₂ is half of the concentration of H₂</u>:

  • [S₂] = [H₂] / 2 = 0.036 M / 2 = 0.018 M

Now we <u>can calculate [H₂S]</u>:

  • 7.5 = [H₂S]² / (0.018*0.036²)
  • [H₂S] = 0.013 M

So 0.013 M is the concentration of H₂S <em>at equilibrium</em>.

  • This would amount to (0.013 M * 2.0 L) 0.026 moles of H₂S
  • The moles of H₂ at equilibrium are equal to the moles of H₂S that reacted.

Initial moles of H₂S - Moles of H₂S that reacted into H₂ = Moles of H₂S at equilibrium

Initial moles of H₂S - 0.072 mol = 0.026 mol

Initial moles of H₂S = 0.098 moles H₂S

8 0
3 years ago
Carbon monoxide is a gas at 0 °c and a pressure of 1.58 × 105 pa. it is a diatomic gas, each of its molecules consisting of one
Hoochie [10]

Given temperature = 0^{0}C = (0^{0} + 273 )K  = 273 K

Pressure = 1.58 ×10^{5} Pa ×\frac{1 atm}{1.01325*10^{5}Pa}

= 1.56 atm

Density =\frac{PM}{RT}

ρ = \frac{(1.56 atm)(28.01 g/mol)}{(0.08206 L.atm/mol.K)(273 K)}

= 1.95 g/L

5 0
3 years ago
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