A bird flying straight upward at 5 m/s drops a berry when it is 300 m above the ground. How fast is the berry going when it hits
the ground (neglect air resistance) ___ m/s.
1 answer:
Answer:
v=77.62 m/s
Explanation:
Given that
h= - 300 m
speed of the bird ,u= 5 m/s
Lets take Speed of the berry when it hit the ground = v m/s
we know that ,if object is moving upward
v² = u² - 2 g h
u=Initial speed
v=Final speed
h=Height
Now by putting the values
v² = u² - 2 g h
v² = 5² - 2 x 10 x (-300) ( take g = 10 m/s²)
v² =25 + 20 x 300
v² ==25 + 6000
v² =6025
v=77.62 m/s
Therefore the final speed of the berry will be 77.62 m/s.
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Answer:
a) h / h₀ = 1,682
, b) h / h₀ = 1.11
, c) h / h₀ = 2.07
Explanation:
For this exercise let's look for the growth equation, as they indicate that it is exponential
h = h₀
The initial height is 9 ”, so the constant
h₀ = 9”
Let's use the given values
h = 15.1655”
t = 5 days
h / h₀ =
α = 1 / t ln h / h₀
α = 1/5 ln (15.1655 / 9)
α = 0.104
h = 9 e^{0.104 t}
a) the growth factor is the relationship between the initial value and the current value
h / h₀ =
h / h₀ = 1,682
b) for t = 1 day
h / h₀ =
h / h₀ = 1.11
c) for t = 7 days
h / h₀ = e^{0.104 7}
h / h₀ = 2.07
Answer:
Explanation:
Given data:
v = 220 rms
power factor = 0.65
P = 1250 W
New power factor is 0.9 lag
we knwo that
s = 1923.09 < 49.65^o
s = [1250 + 1461 j] vA
solving for
Faraday