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Yuki888 [10]
2 years ago
8

Which kinetic chain checkpoint should be observed carefully because it controls the movement of the lower extremities? The hip T

he knee The shoulder The head and neck
Physics
1 answer:
stepladder [879]2 years ago
5 0

The hip is the kinetic chain checkpoint which controls the movement of the lower extremities and is denoted as option A.

<h3>What is Hip?</h3>

This part of the body has a ball-and-socket joint and ensures adequate movement of the legs.

The legs and other parts such as ankle etc are referred to as the lower extremities thereby making it the most appropriate choice.

Read more about Hips here brainly.com/question/4977336

#SPJ1

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What does the term “retroperitoneal” mean in the terms of the location of the kidneys ?
lakkis [162]

Answer:

"Retroperitoneal" refers to the back of the peritoneum, the membrane that lines the anatomical space in the abdominal cavity. Kidney stones may cause pain to the organs within the retroperitoneal space. A diagram of the aorta, a retroperitoneal structure.

Explanation:

5 0
3 years ago
How long does it take for a car to change its velocity from 10 m/s to 25 m/s if the acceleration is 5 m/s^2?
Korolek [52]

Answer:five times five is twenty five divded by 10 is 2.5 seconds of acceleration

6 0
3 years ago
A piston raises a weight, then lowers it again to its original height. If the process the system follows as the piston rises is
FinnZ [79.3K]

Answer:

Negative

Explanation:

First law of thermodynamic also known as the  law of conservation of energy states that the total energy of an isolated system is constant; energy can be transformed from one form to another, but can be neither created nor destroyed.

The first law relates  relates changes in internal energy to heat added to a system and the work done by a system by the conservation of energy.

The first law is mathematically given as ΔU  = U_{F} - U_{0} = Q - W

Where Q  = Quantity of heat

            W = Work done

From the first law The internal energy has the symbol U. Q is positive if heat is added to the system, and negative if heat is removed; W is positive if work is done by the system, and negative if work is done on the system.

Analyzing the pistol when it raises in isothermal and when it falls in  isobaric state.The following can be said:

In the Isothermal compression of a gas there is work done on the system to decrease the volume and increase the pressure. For work to be done on the system it is a negative work done then.

In the Isobaric State An isobaric process occurs at constant pressure. Since the pressure is constant, the force exerted is constant and the work done is given as PΔV.If a gas is to expand at a constant pressure, heat should be transferred into the system at a certain rate.Isobaric is a fuction of heat which is Isothermal Provided the pressure is kept constant.

In Isobaric definition above it can be seen that " Heat should be transferred into the system ata certain rate. For heat to be transferred into the system work is deinitely been done on the system thereby favouring the negative work done.

6 0
3 years ago
A bowling ball has an initial momentum of +30 kg m/s and hits a stationary bowling pin. After the collision, the bowling ball le
dangina [55]

Momentum should be conserved. The momentum of both objects must balance with their initial and final momentum.

Let m1 and v1 be the mass and velocity of the bowling ball

And m2 and v2 be the mass and velocity of the bowling pin

(m1v1)i + (m2v2)i = (m1v1)f + (m2v2)f

30 kg m/s + (1.5 kg)(0 m/s) = 13kg m/s + 1.5v2f

V2f = 11.33 m/s

<span>So the momentum = 1.5 kg(11.33 m/s) = 17 kg m/s</span>

8 0
2 years ago
Steel blocks A and B, which have equal masses, are at TA = 300 oC and T8 = 400 oC. Block C, with mc - 2mA, is at TC = 350 oC. Bl
shepuryov [24]

Answer:

b) TA = TB = TC

Explanation:

  • When put in contact each other, and isolated, both blocks will exchange heat till they reach to thermal equilibrium.
  • During this process, the body at a higher temperature, will loss heat, tat it will be gained by the other body.
  • The equilibrium condition will be reached when the following equation be met:

       \Delta Q = c_{st}* m_{A} * (T_{fin}  - T_{0A} ) = c_{st}* m_{B} * (T_{0B}  - T_{fin} )

  • Replacing by the values of T₀A = 300º C, and T₀B = 400ºC, and simplifying common terms as mA = mB, we can solve for  Tfin, as follows:

       (400 \ºC - T_{fin}) = (T_{fin} - 300 \ºC) \\ \\  2* T_{fin} = 700\ºC\\ \\ T_{fin} = 350\ºC

  • So, when both blocks reach to equilibrium, they will be at a common final temperature, 350ºC.
  • When put in contact with block C, at the same temperature, at that instant, the three blocks will have the same common temperature of 350 ºC.
  • So, option b) is the right one.
8 0
3 years ago
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