Answer:
To distinguish results based on the only two variables of
awareness.
Explanation:
Answer:
holis como tas me ayudas con mi tare plis
Answer:
a) P=0.25x10^-7
b) R=B*N2*E
c) N=1.33x10^9 photons
Explanation:
a) the spontaneous emission rate is equal to:
1/tsp=1/3 ms
the stimulated emission rate is equal to:
pst=(N*C*o(v))/V
where
o(v)=((λ^2*A)/(8*π*u^2))g(v)
g(v)=2/(π*deltav)
o(v)=(λ^2)/(4*π*tp*deltav)
Replacing values:
o(v)=0.7^2/(4*π*3*50)=8.3x10^-19 cm^2
the probability is equal to:
P=(1000*3x10^10*8.3x10^-19)/(100)=0.25x10^-7
b) the rate of decay is equal to:
R=B*N2*E, where B is the Einstein´s coefficient and E is the energy system
c) the number of photons is equal to:
N=(1/tsp)*(V/C*o)
Replacing:
N=100/(3*3x10^10*8.3x10^-19)
N=1.33x10^9 photons
Answer:
The distance spring compresses (x) = 0.0811 m
Explanation:
Spring constant (k) = 185 N / m
mass (m) = 1.53 kg
When mass is placed upon the spring the spring force is equal to weight of the mass.
⇒ Spring force (F) = weight of object
⇒ Spring force (F) = k × x
And weight of the object = mg
⇒ k x = mg -----------------(1)
Put all the values in equation (1) we get
⇒ 185 × x = 1.53 × 9.81
⇒ x = 0.0811 m
This the distance spring compresses, when mass is placed upon it.
Answer:
The magnitude of the magnetic field at the center of the loop is 3.846 x 10⁻⁵ T.
Explanation:
Given;
number of turns of the flat circular loop, N = 18 turns
radius of the loop, R = 15.0 cm = 0.15 m
current through the wire, I = 0.51 A
The magnetic field through the center of the loop is given by;
Where;
μ₀ is permeability of free space = 4π x 10⁻⁷ m/A
Therefore, the magnitude of the magnetic field at the center of the loop is 3.846 x 10⁻⁵ T.
