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2 years ago

A plane starts from rest accelerates to 40 m/s in 10 seconds. How far did the plane travel during this time?

Physics

1 answer:

tatuchka [14]2 years ago

3 0

<h3>Answer:</h3>

200 m

<h3>Explanation:</h3>

We are given:

Initial velocity of the plane (u) = 0 m/s

Final velocity of the plane (v) = 40 m/s

Time interval (t) = 10 seconds

Displacement of the plane (s) = x m

Solving for x:

Acceleration of the plane

v = u + at [First equation of motion]

40 = 0 + a(10) [replacing known variables]

a = 4 m/s² [dividing both sides by 10]

Displacement of the Plane:

s = ut + 1/2 (at²) [Second equation of motion]

s = (0)(10) + 1/2(4)(10)² [replacing known variables]

s = 200 m

Hence, the Plane covers a distance of 200 m in the given time interval

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