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2 years ago

A plane starts from rest accelerates to 40 m/s in 10 seconds. How far did the plane travel during this time?

Physics

1 answer:

tatuchka [14]2 years ago

3 0

<h3><u>Answer:</u></h3>

200 m

<h3><u>Explanation:</u></h3>

<u>We are given:</u>

Initial velocity of the plane (u) = 0 m/s

Final velocity of the plane (v) = 40 m/s

Time interval (t) = 10 seconds

Displacement of the plane (s) = x m

<u>Solving for x:</u>

<u>Acceleration of the plane</u>

v = u + at [<em>First equation of motion</em>]

40 = 0 + a(10) [<em>replacing known variables</em>]

a = 4 m/s² [<em>dividing both sides by 10</em>]

<u>Displacement of the Plane:</u>

s = ut + 1/2 (at²) [<em>Second equation of motion</em>]

s = (0)(10) + 1/2(4)(10)² [<em>replacing known variables</em>]

s = 200 m

Hence, the Plane covers a distance of 200 m in the given time interval

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