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Alchen [17]
3 years ago
12

She sights two sailboats going due east from the tower. The angles of depression to the two boats are 42o and 29o. If the observ

ation deck is 1,353 feet high, how far apart are the boats?

Physics
1 answer:
Reika [66]3 years ago
3 0

Answer:

The boats are  934.65 feet apart

Explanation:

Given:

The angles of depression to the two boats are 42 degrees and 29 degrees

Height of the observation deck i =  1,353 feet

To Find:

How far apart are the boats (y )= ?

Solution:

<em><u>Step 1 : Finding the value of x(Refer the figure attached)</u></em>

We can use the tangent ratio to find the x value

tan(42^{\circ}) = \frac{1353}{x}

x = \frac{1353}{tan(42^{\circ}) }

x = 590.47 feet

<em><u>Step 2 : Finding the value of  z (Refer the figure attached)</u></em>

tan(29^{\circ}) = \frac{1353}{z }

z  = \frac{1353}{tan(29^{\circ})}

z = 1525.12  feet

<em><u>Step 3 : Finding the value of  y (Refer the figure attached</u></em>)

y =  z -x

y = 1525.12 - 590.47

y = 934.65 feet

Thus the two boats are 934.65 feet apart

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