Answer:
Amplitude is decreased by a factor of
if intensity is decreased by a factor of 3.
Explanation:
Intensity of a sound wave is directly proportional to the square of its amplitude.
Therefore, if intensity is
and amplitude is
, then
, where,
is constant of proportionality.
Now, if intensity of sound wave is decreased by a factor of 3. So,
New intensity is, 

Plug in
for
. This gives,

Therefore, amplitude is decreased by a factor of
.
Answer:
All of the arrows pointing up that have a red box NOT the arrow pointing down with a red box. (if the blue squigglies on the water are arrows then they count too, the picture is not too clear)
Explanation:
Gravitational attraction / field strength increases when closer; A light dependent resistor (LDR) can be used as a sensor to detect light intensity.
Answer:
After finding the electric potential VP at point P = Q/Чπϵ₀L ㏑(1+
)
Explanation:
I believe it is a part C question.
The derivative of V and P will be directly proportional to the differential dq and the inverse of Чπϵ₀δ........
Please find detailed solution in the attached picture as i believe that is the answer to the part C question you are seeking for.