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3 years ago

you hold a mug of hot chocolate to warm your hands. Which type of heat transfer are you demonstrating?

Physics

2 answers:

olasank [31]3 years ago

7 0

Explanation:

Conduction is the transfer of heat through direct contact. Whereas convection is the transfer of heat through the currents which generate by warming or cooling of liquids or gases.

On the other hand, radiation is the direct transfer of electromagnetic waves in the form of heat through the space.

Therefore, when you hold a mug of hot chocolate to warm your hands then due to the direct contact with the mug your hands get warmer.

Hence, this transfer of heat is through the process of conduction.

Sergio [31]3 years ago

6 0

<span>Some flows into your hands by conduction, some is lost to the surrounding air by convection</span>

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The orbital radius of an electron in a hydrogen atom is 0.846 nm. What is its de Broglie wavelength?

kotykmax [81]

Answer:

The value is $\lambda = 1.329 *10^{-9} \ m$

Explanation:

From the question we are told that

The orbital radius is $r = 0.846nm = 0.846 *10^{-9} \ m$

Generally the de Broglie wavelength is mathematically represented as

$\lambda = \frac{2 * \pi r}{4}$

substituting values

$\lambda = \frac{ 2 * 3.142 * 0.846 *10^{-9}}{4}$

$\lambda = 1.329 *10^{-9} \ m$

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3 years ago

An electrical motor spins at a constant 1975.0 rpm. If the armature radius is 7.112 cm, what is the acceleration of the edge of

stealth61 [152]

Answer:

Option D is the correct answer.

Explanation:

Since value of angular acceleration is constant, the body has only centripetal acceleration.

Centripetal acceleration

$a=\frac{v^2}{r}=\frac{(r\omega )^2}{r}=r\omega ^2$

We have radius = 7.112 cm = 0.07112 m

Frequency, f = 1975 rpm = 32.92 rps

Angular frequency, ω = 2πf = 2 x π x 32.92 = 206.82 rad/s

Substituting in centripetal acceleration equation,

$a=r\omega ^2=0.07112\times 206.82^2=3042.17m/s^2$

Option D is the correct answer.

3 0

4 years ago

A small object with a 5.0-mC charge is accelerating horizontally on a friction-free surface at 0.0050 m/s2 due only to an electr

kolbaska11 [484]

Answer:

$0.002 N/C$

Explanation:

Parameters given:

Charge of object, q = 5 mC = $5 * 10^{-3} C$

Acceleration of object, a = $0.005 m/s^2$

Mass of object, m = 2.0 g

The Electric field exerts a particular force on the object, causing it to accelerate (Electrostatic force).

We know that Electrostatic force, F, is given in terms of Electric field, E, as:

F = qE

This means that the object exerts a force of -qE on the Electric force (Action with equal and opposite reaction).

The object also has a force, F, due to its acceleration a. This force is the product of its mass and acceleration. Mathematically:

F = ma

Equating the two forces of the object, we get:

-qE = ma

=> $E = \frac{-ma}{q}$

Solving for E, we have:

$E = \frac{-2 * 10^{-3} * 0.005}{5 * 10^{-3}} \\\\\\E = -0.002 N/C$

The magnitude will be:

$|E| = |-0.002| N/C = 0.002 N/C$

The electric field has a magnitude of 0.002 N/C.

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3 years ago

What is the acceleration of an object that has a mass of 10kg and is pushed with a force of 50n

worty [1.4K]

Answer:

5m/s/s

Explanation:

force = mass x acceleration

50 = 10a

a=5m/s/s

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3 years ago

If the original pressure is 5 atm and original volume is 100 L, and the new volume is 20 L, what is the new pressure?

Nana76 [90]

P1V1=P2V2
5*100=P2*20
500=20P
P=25

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3 years ago