The work-energy theorem says that the total work done on the block is equal to the difference of its kinetic energies at points B and A. Then the total work done on the block is

Friction acts on the block to oppose its motion, so it does negative work on the block, -4.5 J.
The only other force acting on the block as it moves is the force <em>P</em>. Let
be the work done by the force <em>P</em>. Then the total work done on the block is

By increasing or decreasing the height, we can do that....
Answer:
The magnitude of the force per unit length is 2.145 x 10⁻⁵ N/m and the direction of the force is outward or repulsive since the current in the two parallel wires are flowing in opposite direction.
Explanation:
Given;
distance between the parallel wires, r = 5.0 cm = 0.05 m
current in the first wire, I₁ = 1.65 A
current in the second wire, I₂ = 3.25 A
The magnitude of the force per unit length between the two wires is calculated as follows;

Therefore, the magnitude of the force per unit length is 2.145 x 10⁻⁵ N/m and the direction of the force is outward or repulsive since the current in the two parallel wires are flowing in opposite direction.
Answer:
a. β = 8.23 K
b. β = 28.815 K
Explanation:
Heat pump can be find using the equation
β = TH / TH - TC
a.
TH = 15 ° C + 273.15 K = 288.15 K
TC = - 20 ° C + 273.15 K = 253.15 K
β = 288.15 K / 288.15 k - ( 253.15 K )
β = 8.23 K
b.
TH = 15 ° C + 273.15 K = 288.15 K
TC = 5 ° C + 273.15 K = 278.15 K
β = 288.15 K / 288.15 k - ( 278.15 K )
β = 28.815 K