Find the electric potential VP at point P. [Hint: To input a natural logarithm into the answer box, simply type the letters "ln" (for example ln(x) is the natural logarithm of x).] Express your answer in terms of d, L, Q, and ϵ0.
1 answer:
Answer:
After finding the electric potential VP at point P = Q/Чπϵ₀L ㏑(1+ )
Explanation:
I believe it is a part C question.
The derivative of V and P will be directly proportional to the differential dq and the inverse of Чπϵ₀δ........
Please find detailed solution in the attached picture as i believe that is the answer to the part C question you are seeking for.
You might be interested in
The answer to this question is: C) Meteor Shower
It can be measured by an ammeter.
Answer:
Explanation:
Given:
quantity of point charge, radial distance from the linear charge, linear charge density, <u>We know that the electric field by the linear charge is given as:</u>
<u>Now the force on the given charge can be given as:</u>
Answer:
Acceleration = 10.06 m/s²
Explanation:
1 mile = 1.6093km
1609.3m = 1 mile
1 m = mile
50.0 miles/hour = m/s
= 22.35m/s
from equation
S = Ut + 1/2 at²
v = U + at
22.35 = 0 + a * 2.22
a = 22.35 ÷ 2.22
= 10.06 m/s²
The gravitational force is inversely proportional to the square of the distance between their centers. So the force is greatest when the distance is zero.