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aliya0001 [1]
3 years ago
5

Definition: This is a drawing showing the direction and magnitude of all forces acting on a body.

Physics
1 answer:
Lisa [10]3 years ago
5 0

Answer:

Free body diagram

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A 3.8kw elective motor powers an inclined conveyer belt. It is designed to lift heavy boxes from the warehouse floor to loading
zhannawk [14.2K]

Answer:

See the answers below

Explanation:

To solve this problem we must use the definition of power and work in physics.

a)

The function of the conveyor belt is to carry the boxes from an initial point that is at low altitude to an end point that is at high altitude. In this way the conveyor belt prints a speed to the box to be able to raise it to the required vertical distance.

Since we have a velocity at the beginning and then we place the box at a high position, where then the box remains at rest, we can say that it converts kinetic energy to potential energy.

b)

Power is defined as the relationship of work over time. Therefore we have:

P=W/t

where:

P = power = 3.8 [kW] = 3800 [W]

W = work [J]

t = time = 14 [s]

W=P*t\\W=3800*14\\W= 53200[J] = 53.2[kJ]

c)

Since the given time is equal to the given time at Point b, we can use the same work calculated.

We know that work is defined as the product of force by the distance traveled.

W =F*d

So, the force is equal to:

F=W/d\\F=53200/5.3\\F=10037.73[N]

Now we know that force is defined as the product of mass by gravitation acceleration.

F =m*g

where:

F = force or weight = 10037.73 [N]

g = gravity acceleration = 9.81 [m/s²]

m = mass [kg]

m=F/g\\m = 10037.73/9.81\\m = 1023.2 [kg]

d)

This part can be solved by means of the energy conservation theorem, where the potential energy is transformed into kinetic energy or vice versa.

E_{pot}=m*g*h = E_{kin}=0.5*m*v^{2}

where:

h = elevation = 4.7 [m]

v = velocity [m/s]

m*g*h=0.5*m*v^{2}\\g*h=0.5*v^{2} \\v=\sqrt{\frac{g*h}{0.5} } \\v=\sqrt{\frac{9.81*4.7}{0.5} }   \\v = 9.6 [m/s]

7 0
3 years ago
What is law of conservation of momentum ?​
Black_prince [1.1K]

Answer:

conservation of momentum, general law of physics according to which the quantity called momentum that characterizes motion never changes in an isolated collection of objects; that is, the to

8 0
2 years ago
What is the total kinetic energy of a 0.15 kg hockey puck sliding at 0.5 m/s and rotating about its center at 8.4 rad/s
AlexFokin [52]

Answer:

K=0.023J

Explanation:

From the question we are told that:

Mass m=0.15

Velocity v=0.5m/s

Angular Velocity \omega=8.4rad/s

Generally the equation for Kinetic Energy is mathematically given by

K=\frac{1}{2}M(v^2+\frac{1}{2}R^2\omega^2)

K=\frac{1}{2}0.15(0.5^2+\frac{1}{2}(0.038)^2.(8.4rad/s^2))

K=0.023J

8 0
2 years ago
1. While John is traveling along an interstate highway, he notices a 160-mile marker as he passes through town. Later John passe
pogonyaev

Number of miles that marker shows when passes through town= 160 miles.

Number of miles that marker shows currently to John = 115 miles.

We need to find the distance between town and John's current location.

For the problem, we can clearly see that Town is at 160 miles away but when John passes the marker shows 115 miles.

So, it's just the difference between 160 miles and 115 miles.

In order to find that difference, we need to subtract those two numbers.

160miles - 115miles = 45 miles.

So, we could say the distance between town and John's current location is 45 miles.

4 0
3 years ago
An iron anchor of density 7810.00 kg/m^3 appears 252 N lighter in water than in air. (a) What is the volume of the anchor?(b) Ho
RSB [31]

Answer:

(a)The volume of the iron anchor = 25.2 m³

<em>(b)The mass of iron = 196812 kg</em>

Explanation:

<em>Density:</em> This is the ratio of the mass of a body to its volume. The S.I unit of density is <em>kg/m³</em>

(a)

From Archimedes principle, the iron will displace a volume of water that is equal to its volume. And the weight of water displaced is equal to loss in weight or upthrust.

Therefore, Upthrust = lost in weight = weight of water displace.

Therefore, Volume of the iron = mass of water displace/density of water

Vi = m₁/D₁........................... Equation 1

Where Vi = volume of iron, m₁ = mass of water displaced, D₁ = Density of water.

<em>Given: upthrust = 252 N, ∴ m₁ = 252/10 = 25.2 kg.</em>

<em>Constant: D₁ = 1.0 kg/m³</em>

<em>Substituting these values into equation 1,</em>

Vi = 25.2/1.0

Vi = 25.2 m³

Therefore the volume of the iron anchor = 25.2 m³

(b)

<em>Density of the iron = mass of the iron/volume of the iron.</em>

<em>Therefore, Mass of the iron = Density of the iron × volume of the iron...........................................equation 2</em>

<em>Given: Density of the iron = 7810 kg/m³, Volume of the iron =  25.2 m³</em>

<em>Substituting these values into equation 2,</em>

<em>Mass of the iron = 7810×25.2</em>

<em>Mass of the iron  = 196812 kg.</em>

<em>Therefore the mass of iron = 196812 kg</em>

8 0
3 years ago
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