Answer:
Explanation:
The problem is based on Doppler's effect , for which expression is as follows
n is apparent frequency , n₀ is original frequency , V is velocity of light , v₀ is velocity of observer and v_s is velocity of source , both coming towards each other.
Putting the values
n = 302 .
Answer:
She can make have 30 jars with raspberries in them with 50 left over.
Explanation:
1,700 divided by 55
30 equally
but 50 left over
This means that she can make have 30 jars with raspberries in them with 50 left over.
Answer:
1) Pm₂ = 1.9 10⁴ Pa
, b) P_feet = 5.4 10⁴ Pa
, c) Pm₄ = 4.4 10⁴ Pa
Explanation:
a) Pressure can be found using Bernoulli's equation
P₁ + ½ rho v₁² + rho g y₁ = P₂ + ½ rho v₂² + rgo g y₂
The amount of blood that runs through the constant system, all the blood that reaches the brain leaves it, so we can assume that the speed of entry and exit of the total blood is the same. In this case the equation is
P₁-P₂ = rgo h (y₂-y₁)
The gauge pressure is
Pm = P₁ -P₂
Pm₂ = 1.06 10³ 9.8 1.83
Pm₂ = 19 10³ Pa
Pm₂ = 1.9 10⁴ Pa
The pressure in the heart is
Pm₁ = 246 torr (1,013 10⁵ Pa / 760 torr) = 3,279 10⁴ Pa
Therefore the gauge pressure is an order of magnitude less
Total or absolute pressure is
Pm₂ = P_heart - P_brain
P_brain = P_heart - Pm₂
P brain = 3,279 10⁴ - 1.9 10⁴
P brain = 1.4 104 Pa
b) on the feet
Pm₃ = rho g y₃
y = 2.04 m
Pm₃ = 1.06 10³ 9.8 2.04
Pm₃ = 21 10³ Pa
Pm₃ = 2.1 10⁴ Pa
Total pressure
Pm₃ = P_feet + P_heart
P_feet = Pm₃ + P_heart
P_feet = 3,279 10⁴ + 2.1 10⁴
P_feet = 5.4 10⁴ Pa
c) If you lower your head the height change is
h = 1.83 +2.04
h = 4.23 m
Pm₄ = 1.06 10³ 9.8 4.23
Pm₄ = 4.4 10⁴ Pa
Answer:
d = 0.25 mm
Explanation:
The position that the Minimal fall in single silt diffraction pattern can be written as
y=λmD/d ..........eqn(1)
(y2 - y1 )= difference of y that exist between first and second minima
D= distance of slit from the screen=1.50m
d= width of the slit
λ= 633 nm = 633×10^-9m
y= position of pth minimal
eqn(1) can be written as
(y2 - y1)= λmD/d .........eqn(2)
If we substitute the given values we have
(y2 - y1 )= [ (2×633×10^-9 × 1.50) /d] -[ (1×633×10^-9 × 1.50) /d]
Simplyfying
(y2 - y1)=(9.495×10^-7)/d
But The distance between the first and second minima in the diffraction pattern = 3.75, which implies that (y2 - y1) = 3.75mm=
✓ we can substitute (y2 - y1)= 3.75mm=3.75 ×10^-3 into expression above
3.75 ×10^-3 =(9.495×10^-7)/d
The we can make "d" subject of the formula
d=(9.495×10^-7)/ (3.75 ×10^-3)
d=0.00025m
d=0.25×10^-3 m
d=0.25 mm
Hence, the width (in mm) of the slit is 0.25mm