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Firlakuza [10]
3 years ago
14

Which of the following conditions would always result in a net force of 0N?

Physics
2 answers:
9966 [12]3 years ago
7 0

A condition which would always result in a net force of zero (0) Newton is: A. Two equal but opposite forces act on an object.

Newton's Second Law of Motion states that the acceleration of an object is inversely proportional to its mass and directly proportional to the net force acting on the physical object.

Mathematically, Newton's Second Law of Motion is given by this formula;

Acceleration = \frac{Net \; force}{Mass}

According to Newton's Second Law of Motion, the acceleration of a physical object occurs when there is a net force on an object while a net force (sum of all the forces) zero (0) causes no acceleration.

In Science, an object is said to be at equilibrium when two equal but opposite forces are acting on it and this would always result in a net force of zero (0) Newton.

<u>For example:</u>

0 N = 5N + (-5N)\\\\0N = 5N - 5N

Read more here: brainly.com/question/24029674

grigory [225]3 years ago
4 0

Answer:

An object is at rest

Explanation:

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An insulating sphere is 8.00 cm in diameter and carries a 6.50 µC charge uniformly distributed throughout its interior volume.
Kobotan [32]

Explanation:

(a)   Formula to calculate the density is as follows.

            \rho = \frac{Q}{\frac{4}{3}\pi a^{3}}

                       = \frac{6.50 \times 10^{-6}}{\frac{4}{3} \times 3.14 \times (0.04)^{3}}

                     = 2.42 \times 10^{-2} C/m^{3}

Now, calculate the charge as follows.

            q_{in} = \rho(\frac{4}{3} \pi r^{3})

                      = 2.42 \times 10^{-2} C/m^{3} \times 4.1762 \times (0.01)^{3}

                      = 10.106 \times 10^{-8} C

or,                   = 101.06 nC

(b)  For r = 6.50 cm, the value of charge will be calculated as follows.

                q_{in} = \frac{Q}{\frac{4}{3}\pi a^{3}}

                          = \frac{6.50 \times 10^{-6}}{\frac{4}{3} \times 3.14 \times (0.065)^{3}}

                          = 7.454 \mu C

7 0
3 years ago
Describe the motion of a swing that requires 6 seconds to complete one cycle. What is its period and the frequency? Round to the
shutvik [7]

Period = 6 seconds and frequency = 0.167Hz .

<u>Explanation:</u>

We have , the motion of a swing that requires 6 seconds to complete one cycle. Period is the amount of time needed to complete one oscillation . And in question it's given that 6 seconds is needed to complete one cycle. Hence ,Period of the motion of a swing is 6 seconds . Frequency is the number of vibrations produced per second and is calculated with the formula of  \frac{1}{t} . SI unit of frequency is Hertz or Hz. We know that time period is 6 seconds so frequency =   \frac{1}{t}

⇒ frequency = \frac{1}{time}

⇒ frequency = \frac{1}{6}

⇒ frequency = 0.167Hz

Therefore , Period = 6 seconds and frequency = 0.167Hz .

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3 years ago
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Vikki [24]

Explanation:

see, torque=force × perpendicular distance

...that perpendicular distance is between axis of rotation and the point where force acts... so in above's case perpendicular distance is zero... so the torque is zero!

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telo118 [61]
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distance = speed * time

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