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Firlakuza [10]
2 years ago
14

Which of the following conditions would always result in a net force of 0N?

Physics
2 answers:
9966 [12]2 years ago
7 0

A condition which would always result in a net force of zero (0) Newton is: A. Two equal but opposite forces act on an object.

Newton's Second Law of Motion states that the acceleration of an object is inversely proportional to its mass and directly proportional to the net force acting on the physical object.

Mathematically, Newton's Second Law of Motion is given by this formula;

Acceleration = \frac{Net \; force}{Mass}

According to Newton's Second Law of Motion, the acceleration of a physical object occurs when there is a net force on an object while a net force (sum of all the forces) zero (0) causes no acceleration.

In Science, an object is said to be at equilibrium when two equal but opposite forces are acting on it and this would always result in a net force of zero (0) Newton.

<u>For example:</u>

0 N = 5N + (-5N)\\\\0N = 5N - 5N

Read more here: brainly.com/question/24029674

grigory [225]2 years ago
4 0

Answer:

An object is at rest

Explanation:

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What is the frequency of an electromagnetic wave that has a wavelength of 300,000 km? (the speed of light is 300,000 km/s.)?
expeople1 [14]
Frequency represents the number of complete oscillations in one second. it is measured in Hertz (Hz). Electromagnetic waves are waves which do not require a material media for transmission. They travel with a speed of light.
The speed (m/s) of a wave is given by  frequency (Hz) × Wavelength (m)
Speed is 300,000 km/sec or 300,000,000 m/s and the wavelength is 300,000  km or 300,000,000 m.
Frequency = speed÷ wavelength
                 = 300000000 ÷ 300000000 = 1
Therefore, the frequency of the wave is 1Hz

6 0
3 years ago
A 20.5 kg ball moving at 38.5 m/s on a horizontal, frictionless surface runs into a light spring of force
tekilochka [14]

Answer:

7.68 m

Explanation:

Kinetic energy in ball = elastic energy in spring

KE = EE

½ mv² = ½ kx²

mv² = kx²

x = v √(m / k)

x = (38.5 m/s) √(20.5 kg / 515 N/m)

x = 7.68 m

5 0
3 years ago
Determine the velocity required for a moving object 2.00 x 10^4 m above the surface of Mars to escape from Mars's gravity. The m
Ket [755]

Answer:

Therefore the escape velocity from Mar's gravity is 15.88 \times 10^4 m/s.

Explanation:

Escape velocity: Escape velocity is a the minimum velocity that a object needs to escape from the gravitational field of massive body.

V_{escape}=\sqrt{\frac{2GM}{R}}

V_{escape}= Escape velocity

G=Universal gravitational constant = 6.673×10⁻¹¹N m²/Kg²

M= mass of Mars = 6.42×10²³ kg

R = Radius of the Mars = 3.40×10³m

The escape velocity does not depend on the velocity of a object.

V_{escape}=\sqrt{\frac{2\times6.673\times 10^{-11}\times 6.42\times 10^{23}}{3.40\times10^3}}

           =15.88 \times 10^4 m/s

Therefore the escape velocity from Mar's gravity is 15.88 \times 10^4 m/s.

           

3 0
3 years ago
I need help solving both of the questions fast please!!!!!!
sergey [27]
I haven´t learned that yet I´m sorry.
6 0
3 years ago
A car is stopped at a traffic light. It then travels along a straight road so that its distance from the light is given by x(t)=
True [87]

Answer:

(a) average velocity = 17.6 m/s

(b) when t = 0, v = 0

    when t = 4, v = 19.2 m/s

    when t = 8, v = 28.8 m/s

(c) after starting from rest, the car will be at rest again in 20 s

Explanation:

Given;

x(t)=bt²−ct³, substitute the given values and the equation will become;

x(t)=3t²−0.1t³

(a)average velocity = total distance / total time

total distance, x(t) = 3t²−0.1t³

x(8) = 3t²−0.1t³

X(8) = 3(8)² - 0.1(8)³

X(8) = 140.8 m

total time = 8 s

average velocity = 140.8 / 8

average velocity = 17.6 m/s

(b) instantaneous velocity = dx / dt

dx / dt = 6t - 0.3t²

when t = 0

v = 0

when t = 4 s

v = 6(4) - 0.3(4²) = 19.2 m/s

when t = 8 s

v = 6(8) - 0.3(8²) = 28.8 m/s

(c) the velocity is zero at dx / dt = 0

6t - 0.3t² = 0

t(6 - 0.3t) = 0

t = 0    or  6 - 0.3t = 0

t = 0     or   0.3t = 6

t = 0      or   t = 6 / 0.3

t= 0       or    t =  20 s

After starting from rest, the car will be at rest again in 20 s

6 0
3 years ago
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