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erma4kov [3.2K]
2 years ago
9

Objects change their speed and/or direction only when

Physics
1 answer:
tensa zangetsu [6.8K]2 years ago
7 0

Answer:

When an external force acts upon them

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What did Thomson’s model of the atom include that Dalton’s model did not have?
astraxan [27]

Answer: Option (d) is the correct answer.

Explanation:

Dalton's model of atom states that every matter is made up of atoms and these atoms are indivisible in nature.

On the other hand, Thomson's model of atom states that there are small particles present in an atom that has positive or negative charges.

Thomson's model of atom is also known as plum pudding model where negatively charged particles are represented by plum and positively charged particles are represented by pudding.

Thus, we can conclude that Thomson’s model of the atom include smaller particles that Dalton’s model did not have.

4 0
3 years ago
Read 2 more answers
1. The potential difference between the terminals a cell in open circuit is 2.2volt. With resistance of 5ohm across the terminal
nadya68 [22]

Explanation:  

10 /9 Ω

potential difference across the cell in open circuit is the emf of the cell.

Hence, emf E=2.2V

when, circuit is closed, potential difference across cell is given by V=E−Ir

And,

I= E/ R+r

Hence, V= E− Er/ R+r

⟹ V= ER/ R+r

⟹ 1.8= 2.2×5 /5+r

⟹9+1.8r=11

⟹ r= 2/  1.8  Ω

⟹ r= 10/9  Ω

​

​

 

7 0
2 years ago
A car slows down at -5.00 m/s² until it comes to a stop after travelling 15.0 m. What was the initial speed of the car?
lapo4ka [179]
<h2>Answer: 12.24m/s</h2>

According to <u>kinematics</u> this situation is described as a uniformly accelerated rectilinear motion. This means the acceleration while the car is in motion is constant.

Now, among the equations related to this type of motion we have the following that relates the velocity with the acceleration and the distance traveled:

V_{f}^{2}-V_{o}^{2}=2.a.d   (1)

Where:

V_{f} is the Final Velocity of the car. We are told "the car comes to a stop after travelling", this means it is 0.

V_{o} is the Initial Velocity, the value we want to find

a is the constant acceleration of the car (the negative sign means the car is decelerating)

d is the distance traveled by the car

Now, let's substitute the known values in equation (1) and find V_{o}:

0-V_{o}^{2}=2(-5m/{s}^{2})(15m)    (2)

-V_{o}^{2}=-150{m}^{2}/{s}^{2}    (3)

Multiplying by -1 on both sides of the equation:

V_{o}^{2}=150{m}^{2}/{s}^{2}    (4)

V_{o}=\sqrt{150{m}^{2}/{s}^{2}}    (5)

Finally:

V_{o}=12.24m/s >>>This is the Initial velocity of the car

5 0
3 years ago
A 75.0 kg driver slides into a seat in a truck that has only 1 spring. The spring compresses 1.60 cm = 0.0160 m. What is the spr
ValentinkaMS [17]

Answer

0.510

Explanation:

5 0
3 years ago
The speed of light is about 3.00 × 105 km/s. It takes approximately 1.28 seconds for light reflected from the
Ulleksa [173]
Just to correct you - the speed of light is 3.0 x 10^5 km/sec and not 105 km/sec as given by you (maybe it was just a typing mistake from your end).

The average distance between earth and moon would be - 384,000 kms. 

This is calculated by the formula -> Distance = Speed x Time.
 

8 0
3 years ago
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