Referred to as Checka. 3x + 7 + -x-1

Mathematics

1 answer:

densk [106]3 years ago

7 0

Answer:

2x+6

Step-by-step explanation:

you would get 2x+6 because you collect like terms and 3x minus 1x is 2x its minus because a negative is subtracting. and then 7 minus 1 is 6

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Find the diameter of a cone that has a volume of 104.67 cubic inches and a height of 4 inches. Use 3.14 for pi. 4 inches 6 inche

aleksandr82 [10.1K]

V: volume of a cone = (πr²h)/3 = 104.67 in³
π: pi = 3.14
r: radius = 1/2 diameter = [unknown]
h: height = 4 in

V = (πr²h)/3
V = r²(πh)/3

r² = (3V)/(πh)
r² = (3 ×104.67)/(3.14 × 4)
r² = 25

r = √25
r = 5 (but remember the radius is only 1/2 the diameter)

thus . . .

d = 10 in 

8 0

3 years ago

Read 2 more answers

PLEASE PLEASE HELP! Find the measure of APB^.

Whitepunk [10]

Answer:

65°

Step-by-step explanation:

Radii CA and CB are perpendicular to tangent lines AT and BT, so

$\angle CAT=\angle CBT=90^{\circ}$

Since angle BAT is equal to 65°, angle CAB has measure

$\angle CAB=90^{\circ}-65^{\circ}=25^{\circ}.$

Consider triangle ACB. This triangle is isosceles, because CA=CB as radii of the circle. Two angles adjacent to the base are congruent, thus

$\angle CBA=\angle CAB=25^{\circ}$

The sum of the measures of all interior angles in triangle is always 180°, so

$\angle CAB+\angle CBA+\angle ACB=180^{\circ}\\ \\25^{\circ}+25^{\circ}+\angle ACB=180^{\circ}\\ \\\angle ACB=130^{\circ}$

Angle ACB is central angle subtended on the minor arc AB, angle APB is inscribed angle subtended on the same minor arc AB. The measure of inscribed angle is half the measure of central angle subtended on the same arc, so

$x=\angle APB=\dfrac{1}{2}\cdot 130^{\circ}=65^{\circ}$