This problem is a combination of the Poisson distribution and binomial distribution.
First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961
For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5) or approximately
=0.00006181
Answer:
B
Step-by-step explanation:
i took the same question hope this helps :D
Answer: 13/24
Step-by-step explanation:
3/8 + 1/6 = 9/24 + 4/24
9 + 4/24 = 13/24
Decimal Form = 0.541667
Hope this helps! #BaconSquad
Answer:
-2+k.5/n
Step-by-step explanation:
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-4j - 1 - 4j + 6 :Combine like terms (-4j and -4j) (-1 and 6)
<em><u>-8j + 5</u></em>