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3 years ago

13

Jesseca Kusher wants to manufacture and sell her new material. Help her marketing campaign by providing a catchy name for the ma

terial, an advertising slogan, and a simple picture for the product label. For the name and slogan, use the drawing tool’s text box feature. lol

1 answer:

Tamiku [17]3 years ago

6 0

Answer: the picture is the answer

Explanation:

You might be interested in

What is the momentum of an animal with a mass of 72kg who is moving with a velocity of 2.2 m/s

ludmilkaskok [199]

Answer:

The answer is

<h2>158.4 kgm/s</h2>

Explanation:

The momentum of an object when given it's mass and velocity can be found by using the formula

<h3>momentum = velocity × mass</h3>

From the question

velocity = 2.2 m/s

mass = 72 kg

The momentum is

momentum = 2.2 × 72

We have the final answer as

<h3>158.4 kgm/s</h3>

Hope this helps you

4 0

4 years ago

On April 15, 1999, a South Korean cargo plane crashed due to a confusion over units. The plane was to fly from Shanghai, China,

sattari [20]

Answer:

993 m or 3257 ft

Explanation:

The captain was told to fly at at 1500 ft altitude. At the rate of 3.28 ft to 1 m, this is

$\dfrac{1500}{3.28}=457$ metres.

Since he was at 1450 m, he thought he was above the correct altitude by

1450 - 457 = 993 m.

In feet, this is

993 * 3.28 = 3257 ft

6 0

4 years ago

The energy transfer diagram represents the energy of a light bulb.

Nikolay [14]

The answer is 80 J of electrical energy

4 0

3 years ago

Read 2 more answers

To calculate the change in kinetic energy, you must know the force as a function of _______. The work done by the force causes t

aliya0001 [1]

To calculate the change in kinetic energy, you must know the force as a function of position. The work done by the force causes the kinetic energy change

Explanation:

The work-energy theorem states that the change in kinetic enegy of an object is equal to the work done on the object:

$\Delta E_k = W$

where the work done is the integral of the force over the position of the object:

$W=\int F(x) dx$

As we see from the formula, the magnitude of the force F(x) can be dependent from the position of the object, therefore in order to solve correctly the integral and find the work done on the object, it is required to know the behaviour of the force as a function of the position, x.

6 0

3 years ago

A trick shot archer shoots an arrow with a velocity of 30.0 m/s at an angle of 20.0 degrees with respect to the horizontal. An a

svlad2 [7]

Answer:

$u'=10.259\ m.s^{-1}$ is the initial velocity of tossing the apple.

the apple should be tossed after $\Delta t=0.0173\ s$

Explanation:

Given:

velocity of arrow in projectile, $v=30\ m.s^{-1}$

angle of projectile from the horizontal, $\theta=20^{\circ}$

distance of the point of tossing up of an apple, $d=30\ m$

<u>Now the horizontal component of velocity:</u>

$v_x=v\ cos\ \theta$

$v_x=30\times cos\ 20^{\circ}$

$v_x=28.191\ m.s^{-1}$

<u>The vertical component of the velocity:</u>

$v_y=v.sin\ \theta$

$v_y=30\times sin\ 20^{\circ}$

$v_y=10.261\ m.s^{-1}$

<u>Time taken by the projectile to travel the distance of 30 m:</u>

$t=\frac{d}{v_x}$

$t=\frac{30}{28.191}$

$t=1.0642\ s$

<u>Vertical position of the projectile at this time:</u>

$h=v_y.t-\frac{1}{2}g.t^2$

$h=10.261\times 1.0642-\frac{1}{2} \times 9.8\times 1.0642^2$

$h=5.3701\ m$

<u>Now this height should be the maximum height of the tossed apple where its velocity becomes zero.</u>

$v'^2=u'^2-2g.h$

$0^2=u'^2-2\times 9.8\times 5.3701$

$u'=10.259\ m.s^{-1}$ is the initial velocity of tossing the apple.

<u>Time taken to reach this height:</u>

$v'=u'-g.t'$

$0=10.259-9.8\times t'$

$t'=1.0469\ s$

<u>We observe that </u> $t>t'$ <u> hence the time after the launch of the projectile after which the apple should be tossed is:</u>

$\Delta t=t-t'$

$\Delta t=1.0642-1.0469$

$\Delta t=0.0173\ s$

8 0

4 years ago