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Alexeev081 [22]
3 years ago
11

Two students measure the speed of light. One obtains (3.001 0.001)10^8 m/s; the other obtains (2.999 0.006)10^8 m/s.Required:Whi

ch is more precise?
Physics
1 answer:
marin [14]3 years ago
6 0

Answer:

(30010001) 10^8 m/s

Explanation:

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What is the shadow zone of an earth quake?
Nadusha1986 [10]

Answer:

It is the area on opposite side of the earth from an earthquake where no s waves are picked up by seismographs.

Explanation:

Shadow zone of an earthquake is one which is farthest from the epicenter. Hence it is not the area closest to earthquake.

In shadow zone only the S waves are stopped by whereas P waves through refracted, travel through and are measured in seismograph. Hence it is an area where there are few seismographs.

The zone is not constant and each epicenter has its own shadow zone. The shadow zone was caused by the inability of s waves to pass through the liquids. This proved the presence of liquid layer in earth's core. Hence the shadow zone is not the outer molten core of earth but the zone was caused by the molten core.

Hence the shadow zone of an earth quake  is the area on opposite side of the earth from an earthquake where no s waves are picked up by seismographs.

8 0
3 years ago
The velocity of an object is the _____ of the object
katovenus [111]
D. Speed and direction, this is because velocity is a vector quantity so has a magnitude and direction assigned to it because it is the rate of change of displacement.
6 0
3 years ago
___________ charges a neutral body by touching it with a charged body.
k0ka [10]
The correct answer would be cells
4 0
3 years ago
10. If red and yellow paint are mixed together, which color of light will be reflected?
Y_Kistochka [10]

Answer:

The color you get for mixing red and yellow is orange.

Explanation:

Minecraft logic

7 0
3 years ago
A sled with no initial velocity accelerates at rate of 5.0 m/s^2 down a hill . How long does it take the sled to go 45 m to the
Leya [2.2K]

The time taken by the sled to reach 45 m to the bottom is 4.24 s.

The sled's initial velocity <em>u</em> is zero. It has an acceleration <em>a</em> of a value 5 m/s² down the hill and it travels a distance <em>s</em> equal to 45 m down the hill.

Use the equation of motion,

s=ut+\frac{1}{2} at^2

Substitute 0 m/s for u and rewrite the equation for t.

t=\sqrt{\frac{2s}{a}}  \\ =\sqrt{\frac{2(45 m)}{5.0m/s^2} } \\ =4.24s

The sled takes a time of 4.24 s to reach the bottom of the hill

6 0
4 years ago
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