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Pachacha [2.7K]
4 years ago
5

3. Describe the process of heat transfer by conduction. What happens to the molecules that cause the thermal energy to be transf

erred?
Chemistry
1 answer:
ivanzaharov [21]4 years ago
7 0
It is transferred by conduction when two objects at two different temps touch each other, and the one with the most heat will transfer its heat to the cooler object until they both have the same temperature..
At the point of touching the fast moving molecules of the warmer object will collide with the slower moving molecules of the cooler object.
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A 45.0-gram sample of copper metal was heated from 20.0°C to 100.0°C. Calculate the heat absorbed, in kJ, by the metal.
s2008m [1.1K]

Answer:

1.386 KJ

Explanation:

From the question given above, the following data were obtained:

Mass (M) of copper = 45 g

Initial temperature (T1) = 20.0°C

Final temperature (T2) = 100.0°C

Heat absorbed (Q) =..?

Next, we shall determine the change in temperature. This can be obtained as follow:

Initial temperature (T1) = 20.0°C

Final temperature (T2) = 100.0°C

Change in temperature (ΔT) =?

ΔT = T2 – T1

ΔT = 100 – 20

ΔT = 80 °C

Next, we shall determine the heat absorbed by the sample of copper as follow:

Mass (M) of copper = 45 g

Change in temperature (ΔT) = 80 °C

Specific heat capacity (C) of copper = 0.385 J/gºC

Heat absorbed (Q) =..?

Q = MCΔT

Q = 45 × 0.385 × 80

Q = 1386 J

Finally, we shall convert 1386 J to KJ. This can be obtained as follow:

1000 J = 1 KJ

Therefore,

1386 J = 1386 J × 1 KJ /1000 J

1386 J = 1.386 KJ

Thus, the heat absorbed by the sample of the sample of copper is 1.386 KJ.

5 0
3 years ago
Calculate the density of an object with a mass of 30g and volume of 6cm^3
Kipish [7]
Density = Mass ÷ Volume

D= 30g ÷ 6 cm^3

D= 5 g/dm^3

3 0
3 years ago
Whenever you see an ‘N’, ‘S’, or ‘P’ followed by a bunch of oxygens you know you have a
Leya [2.2K]
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4 0
3 years ago
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For each of the following cases, identify the order with respect to the reactant, A. Case (A ----> product)
damaskus [11]

Answer:

The answers to the question are

1. 2nd and above order order

2. 2nd order

3. 1/2 order

4.  1st order

5. 0 order

Explanation:

We have \frac{N}{N_{0} } = e^{-\lambda t}

1. For nth order reaction half life  t_{\frac{1}{2} } ∝ \frac{1}{[A_{0} ]^{n-1} }

Therefore for a 0 order reaction increasing concentration of the reactant there will increase   t_{\frac{1}{2} }

First order reaction    is independent  [A₀].

Second order reaction  [A₀] decrease,    increase.

Similarly for a  third order reaction

1. 2nd order

2. 2nd order reaction

3. Order of reaction is 1/2.

4. 1st order reaction.

5. Zero order reaction.

5 0
3 years ago
A gas is initially at a pressure of 4.7 atm and a volume of 7.5 L. When the volume is increased to 10.5 L, what is the new press
Roman55 [17]

Answer:

P2=3.36 atm

Explanation:

P1×V1=P2×V2

P1×V1÷V2=P2×V2÷V2

P2=4.7×7.5÷10.5

P2=3.36 atm

5 0
3 years ago
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