Answer:
See attached image for diagrams and solution
Answer:
a)W=12.62 kJ/mol
b)W=12.59 kJ/mol
Explanation:
At T = 100 °C the second and third virial coefficients are
B = -242.5 cm^3 mol^-1
C = 25200 cm^6 mo1^-2
Now according isothermal work of one mole methyl gas is
W=-![\int\limits^a_b {P} \, dV](https://tex.z-dn.net/?f=%5Cint%5Climits%5Ea_b%20%7BP%7D%20%5C%2C%20dV)
a=![v_2\\](https://tex.z-dn.net/?f=v_2%5C%5C)
b=![v_1](https://tex.z-dn.net/?f=v_1)
from virial equation
![\frac{PV}{RT}=z=1+\frac{B}{V}+\frac{C}{V^2}\\ \\P=RT(1+\frac{B}{V} +\frac{C}{V^2})\frac{1}{V}\\](https://tex.z-dn.net/?f=%5Cfrac%7BPV%7D%7BRT%7D%3Dz%3D1%2B%5Cfrac%7BB%7D%7BV%7D%2B%5Cfrac%7BC%7D%7BV%5E2%7D%5C%5C%20%20%20%5C%5CP%3DRT%281%2B%5Cfrac%7BB%7D%7BV%7D%20%2B%5Cfrac%7BC%7D%7BV%5E2%7D%29%5Cfrac%7B1%7D%7BV%7D%5C%5C)
And
![W=-\int\limits^a_b {RT(1+\frac{B}{V} +\frac{C}{V^2}\frac{1}{V} } \, dV](https://tex.z-dn.net/?f=W%3D-%5Cint%5Climits%5Ea_b%20%7BRT%281%2B%5Cfrac%7BB%7D%7BV%7D%20%2B%5Cfrac%7BC%7D%7BV%5E2%7D%5Cfrac%7B1%7D%7BV%7D%20%20%7D%20%5C%2C%20dV)
a=![v_2\\](https://tex.z-dn.net/?f=v_2%5C%5C)
b=![v_1](https://tex.z-dn.net/?f=v_1)
Now calculate V1 and V2 at given condition
![\frac{P1V1}{RT} = 1+\frac{B}{v_1} +\frac{C}{v_1^2}](https://tex.z-dn.net/?f=%5Cfrac%7BP1V1%7D%7BRT%7D%20%3D%201%2B%5Cfrac%7BB%7D%7Bv_1%7D%20%2B%5Cfrac%7BC%7D%7Bv_1%5E2%7D)
Substitute given values
= 1 x 10^5 , T = 373.15 and given values of coefficients we get
![10^5(v_1)/8.314*373.15=1-242.5/v_1+25200/v_1^2](https://tex.z-dn.net/?f=10%5E5%28v_1%29%2F8.314%2A373.15%3D1-242.5%2Fv_1%2B25200%2Fv_1%5E2)
Solve for V1 by iterative or alternative cubic equation solver we get
![v_1=30780 cm^3/mol](https://tex.z-dn.net/?f=v_1%3D30780%20cm%5E3%2Fmol)
Similarly solve for state 2 at P2 = 50 bar we get
![v_1=241.33 cm^3/mol](https://tex.z-dn.net/?f=v_1%3D241.33%20cm%5E3%2Fmol)
Now
![W=-\int\limits^a_b {RT(1+\frac{B}{V} +\frac{C}{V^2}\frac{1}{V} } \, dV](https://tex.z-dn.net/?f=W%3D-%5Cint%5Climits%5Ea_b%20%7BRT%281%2B%5Cfrac%7BB%7D%7BV%7D%20%2B%5Cfrac%7BC%7D%7BV%5E2%7D%5Cfrac%7B1%7D%7BV%7D%20%20%7D%20%5C%2C%20dV)
a=241.33
b=30780
After performing integration we get work done on the system is
W=12.62 kJ/mol
(b) for Z = 1 + B' P +C' P^2 = PV/RT by performing differential we get
dV=RT(-1/p^2+0+C')dP
Hence work done on the system is
![W=-\int\limits^a_b {P(RT(-1/p^2+0+C')} \, dP](https://tex.z-dn.net/?f=W%3D-%5Cint%5Climits%5Ea_b%20%7BP%28RT%28-1%2Fp%5E2%2B0%2BC%27%29%7D%20%5C%2C%20dP)
a=![v_2\\](https://tex.z-dn.net/?f=v_2%5C%5C)
b=![v_1](https://tex.z-dn.net/?f=v_1)
by substituting given limit and P = 1 bar , P2 = 50 bar and T = 373 K we get work
W=12.59 kJ/mol
The work by differ between a and b because the conversion of constant of virial coefficients are valid only for infinite series
Answer:
(a) E = 0 N/C
(b) E = 0 N/C
(c) E = 7.78 x10^5 N/C
Explanation:
We are given a hollow sphere with following parameters:
Q = total charge on its surface = 23.6 μC = 23.6 x 10^-6 C
R = radius of sphere = 26.1 cm = 0.261 m
Permittivity of free space = ε0 = 8.85419 X 10−12 C²/Nm²
The formula for the electric field intensity is:
E = (1/4πεo)(Q/r²)
where, r = the distance from center of sphere where the intensity is to be found.
(a)
At the center of the sphere r = 0. Also, there is no charge inside the sphere to produce an electric field. Thus the electric field at center is zero.
<u>E = 0 N/C</u>
(b)
Since, the distance R/2 from center lies inside the sphere. Therefore, the intensity at that point will be zero, due to absence of charge inside the sphere (q = 0 C).
<u>E = 0 N/C</u>
(c)
Since, the distance of 52.2 cm is outside the circle. So, now we use the formula to calculate the Electric Field:
E = (1/4πεo)[(23.6 x 10^-6 C)/(0.522m)²]
<u>E = 7.78 x10^5 N/C</u>
The exercise is about finding the missing medical terms from the list below.. See the sentences below for the missing words.
<h3>What are the completed sentences?</h3>
- The outbreak and spread of epidemic diseases, such as swine flu, are tracked by a <u>Public Health Surveillance Team.</u>
- The person who would use equipment to show an image of a baby before birth is a <u>Diagnostic Medical Sonographer.</u>
- The education to become a <u>Medical Practitioner</u> requires more than four years of college.
- When a water source becomes contaminated with an illness-causing bacteria, a <u>Microbiologist</u> could be brought in to study how to get rid of the microorganisms.
Learn more about medical terms at;
brainly.com/question/759368
#SPJ1
Answer:
The answer is "+9.05 kw"
Explanation:
In the given question some information is missing which can be given in the following attachment.
The solution to this question can be defined as follows:
let assume that flow is from 1 to 2 then
Q= 1kw
m=0.1 kg/s
From the steady flow energy equation is:
![m\{n_1+ \frac{v^2_1}{z}+ gz_1 \}+Q= m \{h_2+ \frac{v^2_2}{2}+ gz_2\}+w\\\\\ change \ energy\\\\0.1[1.005 \times 800]-1= 0.01[1.005\times 700]+w\\\\w= +9.05 \ kw\\\\](https://tex.z-dn.net/?f=m%5C%7Bn_1%2B%20%5Cfrac%7Bv%5E2_1%7D%7Bz%7D%2B%20gz_1%20%5C%7D%2BQ%3D%20m%20%5C%7Bh_2%2B%20%5Cfrac%7Bv%5E2_2%7D%7B2%7D%2B%20gz_2%5C%7D%2Bw%5C%5C%5C%5C%5C%20change%20%5C%20energy%5C%5C%5C%5C0.1%5B1.005%20%5Ctimes%20800%5D-1%3D%200.01%5B1.005%5Ctimes%20700%5D%2Bw%5C%5C%5C%5Cw%3D%20%2B9.05%20%5C%20kw%5C%5C%5C%5C)
If the sign of the work performed is positive, it means the work is done on the surrounding so, that the expected direction of the flow is right.