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3 years ago

Shear strain can be expressed in units of either degrees or radians. a)True b)- False

Engineering

1 answer:

ExtremeBDS [4]3 years ago

3 0

Answer:

true

Explanation:

shear strain is define as the ratio of change in deformation to the original length perpendicular to the axes of member due to shear stress.

ε = deformation/original length

strain is a unit less quantity but shear stain is generally expressed in radians but it can also be expressed in degree.

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3 years ago

A 1000-turn coil of wire 1.0 cm in diameter is in a magnetic field that increases from 0.10 T to 0.30 T in 10 ms. The axis of th

ddd [48]

emf generated by the coil is 1.57 V

Explanation:

Given details-

Number of turns of wire- 1000 turns

The diameter of the wire coil- 1 cm

Magnetic field (Initial)= 0.10 T

Magnetic Field (Final)=0.30 T

Time=10 ms

The orientation of the axis of the coil= parallel to the field.

We know that EMF of the coil is mathematically represented as –

E=N(ΔФ/Δt)

Where E= emf generated

ΔФ= change inmagnetic flux

Δt= change in time

N= no of turns*area of the coil

Substituting the values of the above variables

=1000*3.14*0.5*10-4

=.0785

E=0.0785(.2/10*10-3)

=1.57 V

Thus, the emf generated is 1.57 V

4 0

3 years ago

A strip ofmetal is originally 1.2m long. Itis stretched in three steps: first to a length of 1.6m, then to 2.2 m, and finally to

andreyandreev [35.5K]

Answer:

strains for the respective cases are

0.287

0.318

0.127

and for the entire process 0.733

Explanation:

The formula for the true strain is given as:

$\epsilon =\ln \frac{l}{l_{o}}$

Where

$\epsilon =$ True strain

l= length of the member after deformation

$l_{o} =$ original length of the member

Now for the first case we have

l= 1.6m

$l_{o} = 1.2m$

thus,

$\epsilon =\ln \frac{1.6}{1.2}$

$\epsilon =0.287$

similarly for the second case we have

l= 2.2m

$l_{o} = 1.6m$ (as the length is changing from 1.6m in this case)

thus,

$\epsilon =\ln \frac{2.2}{1.6}$

$\epsilon =0.318$

Now for the third case

l= 2.5m

$l_{o} = 2.2m$

thus,

$\epsilon =\ln \frac{2.5}{2.2}$

$\epsilon =0.127$

Now the true strain for the entire process

l=2.5m

$l_{o} = 1.2m$

thus,

$\epsilon =\ln \frac{2.5}{1.2}$

$\epsilon =0.733$

6 0

3 years ago