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3 years ago

How are compounds and mixture alike ?

1 answer:

6 0

Compounds are atoms or molecules that are chemically bonded together to form a different molecule or compound. The process could be written as a chemical reaction. A mixture is when two elements or compounds are mixed together but do not react, ie no chemical reaction between the two occurs.

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A material is nonmagnetic and gaseous and does not conduct heat or electricity. It will, however, react with other elements. It

topjm [15]

Answer:

The correct option is: Nonmetal

Explanation:

Non-metals are the chemical elements that are generally present in the gaseous state at room temperature and have low electrical and thermal conductivity. These elements are non-magnetic and tend to have low density, boiling point and melting point. Non-metals have high electronegativity and ionization energy and react by sharing or gaining electrons from the other elements.

Therefore, the given material is most likely a non-metal.

8 0

4 years ago

Two trains on separate tracks move toward each other. Train 1 has a speed of 145 km/h; train 2, a speed of 72.0 km/h. Train 2 bl

tekilochka [14]

Answer:

Therefore,

The frequency heard by the engineer on train 1

$f_{o}=603\ Hz$

Explanation:

Given:

Two trains on separate tracks move toward each other

For Train 1 Velocity of the observer,

$v_{o}=145\ km/h=145\times \dfrac{1000}{3600}=40.28\ m/s$

For Train 2 Velocity of the Source,

$v_{s}=90\ km/h=90\times \dfrac{1000}{3600}=25\ m/s$

Frequency of Source,

$f_{s}=500\ Hz$

To Find:

Frequency of Observer,

$f_{o}=?$ (frequency heard by the engineer on train 1)

Solution:

Here we can use the Doppler effect equation to calculate both the velocity of the source $v_{s}$ and observer $v_{o}$ , the original frequency of the sound waves $f_{s}$ and the observed frequency of the sound waves $f_{o}$ ,

The Equation is

$f_{o}=f_{s}(\dfrac{v+v_{o}}{v -v_{s}})$

Where,

v = velocity of sound in air = 343 m/s

Substituting the values we get

$f_{o}=500(\dfrac{343+40.28}{343 -25})=500\times 1.205=602.64\approx 603\ Hz$

Therefore,

The frequency heard by the engineer on train 1

$f_{o}=603\ Hz$

7 0

3 years ago

Ear "popping" is an unpleasant phenomenon sometimes experienced when a change in pressure occurs, for example,in an airplane. If

marshall27 [118]

Answer:

H = 0.00058m = 0.58mm of Mercury

h = 160m for popping at 8000m

Explanation:

Air density decreases with altitude (increasing height).

At sea level air density = 1.22kg/m^3

while at 3000m above it is approximately 0.8 kg/m^3

ASSUMPTION:

we neglect the change in density across 100m vertically

density of mercury = 13600kg/m ^3

we equate the pressure for mercury and air

AIR(pgh) = Mercury(pgh)

0.8 * g * 100 = 13600 * g * H

H = 0.00058m = 0.58mm of Mercury

At even farther heights, the air density further drops

at 8000m above it is 0.52kg/ m^3 (source:https://www.engineeringtoolbox.com/standard-atmosphere-d_604.html)

***for the ear to pop again, it has to experience same change in pressure as of at 3000m

Change in P for AIR at 3000m = Change in P for AIR at 8000m

ASSUMPTION : gravitational acceleration does not change with altitude

pgh = pgh

0.8 * g * 100 = .5 * g *h

h = 160m

3 0

4 years ago

How long do a Tortoise live in the earth?

Oksanka [162]

Answer:

80 to 150 years

Explanation:

hope I helped

8 0

3 years ago

Read 2 more answers

Convert 830kg to cg using conversion factor

Len [333]

Answer:

83000000

Explanation:

Conversion factor: 1 kg = 100000 cg

1) Centigram = Kilogram * 100000

2) Centigram = 830 * 100000

3) Centigram = 83000000

~~Hope this helps~~

6 0

3 years ago