Ask question

Ask question

All categories

2 years ago

9

3. When the procedure is repeated with a third line how will it distinguish whether the location of the center of gravity is acc

urate or not?

1 answer:

Law Incorporation [45]2 years ago

4 0

Well this is question is easy. I mean i’m the one to say the least, The answer is.. SIKE L bozo imagine not knowing the answer

You might be interested in

What is the displacement of the runner in 4 laps? *<br> 2 point

Serhud [2]

Answer:

There is no displacement.

Explanation:

Because the runner is running laps and returning to the original place, there is no displacement as displacement is relative to the change in location from the original position.

Hope this helps. . .

ly UwU

3 0

3 years ago

Why oil does not dissolve in water?

suter [353]

Answer:

Explanation:

Oil cannot dissolve in water because oil molecules repel water molecules

3 0

3 years ago

The bell rings and a physics student heads to class. They stop to talk to a few friends. They slow

grin007 [14]

Answer:

420m

Explanation:

Given parameters:

Time = 5minutes

Average speed = 1.4m/s

Unknown:

Distance covered = ?

Solution:

Speed is the rate of change of distance with time.

Mathematically;

Speed = $\frac{distance}{time}$

Distance = speed x time

Insert the parameters and solve;

Convert the time to seconds;

1 minute = 60s

5 minute = 5 x 60 = 300s

So,

Insert the parameters and find the distance;

Distance = 300 x 1.4 = 420m

3 0

3 years ago

A laser is placed at the point $(3,5)$. The laser beam travels in a straight line. Larry wants the beam to hit and bounce off th

Black_prince [1.1K]

Answer:

4units

Explanation:

To calculate the total distance the beam will travel along this path, you will use the formula for calculating the distance between two coordinates expressed as;

D = √(x2-x1)²+(y2-y1)²

Given the coordinate points

(3,5) and (7,5)

Substitute

D = √(7-3)²+(5-5)²

D = √(7-3)²+0²

D = √4²

D = √16

D = 4

Hence the total distance the beam will travel along this path is 4units

6 0

3 years ago

A 108 kg clock initially at rest on a horizontal floor requires a 653 N horizontal force to set it in motion. After the clock is

kifflom [539]

Answer:

$\mu_s=0.61$

$\mu_k=0.49$

Explanation:

Given that,

Mass of the clock, m = 108 kg

When the clock is not moving, force acting on it, $F_1=653\ N$

For the clock in motion, force acting on it, $F_2=527\ N$

To find,

$\mu_s\ and\ \mu_k$

Solution,

When an object is at rest, the force acting on it is called force due to static friction and if the object is in motion, the force acting on its called force due to kinetic friction.

Let $\mu_s$ is the coefficient of static friction. Force is given by :

$F_s=\mu_smg$

$\mu_s=\dfrac{F_s}{mg}$

$\mu_s=\dfrac{653}{108\times 9.8}$

$\mu_s=0.61$

Let $\mu_k$ is the coefficient of kinetic friction. Force is given by :

$F_k=\mu_kmg$

$\mu_k=\dfrac{F_k}{mg}$

$\mu_k=\dfrac{527}{108\times 9.8}$

$\mu_k=0.49$

8 0

3 years ago