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3 years ago

9

3. When the procedure is repeated with a third line how will it distinguish whether the location of the center of gravity is acc

urate or not?

1 answer:

Law Incorporation [45]3 years ago

4 0

Well this is question is easy. I mean i’m the one to say the least, The answer is.. SIKE L bozo imagine not knowing the answer

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Which of the following is the correct definition of conduction? A. the transfer of heat by currents within a liquid or gas B. th

dolphi86 [110]

I believe it's B. the transmission of heat across matter

6 0

3 years ago

Read 2 more answers

PLEASE HELP i really need help with these

enyata [817]

Answer:

21

Explanation:

IDK

7 0

3 years ago

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An Olympic diver springs off of a high dive that is 3 m above the surface of the water. When she lands in the water she is trave

klemol [59]

Answer: $u=4.51 m/s\ at\ angle\ of\ \theta =59.34^{\circ}$

Explanation:

Given

height of building h=3 m

Landing velocity of diver $v=8.90 m/s$ at an angle of $75^{\circ}$

Let u be the initial velocity of diver at an angle of \theta with horizontal

Since there is no acceleration in horizontal direction therefore horizontal component of velocity will remain same

$u\cos \theta =8.9\cos (75)$ ---- -----1

Considering Vertical motion

$v^2-u^2=2as$

here $v=8.9\sin (75)$

$u=u\sin \theta$

$s=3 m$

$a=9.8 m/s^2$

$(8.9\sin (75))^2-(u\sin \theta )^2=2\times 9.8\times 3$

$u\sin \theta =\sqrt{(8.9\sin 75)^2-(2\cdot 9.8\cdot 3)}$

$u\sin \theta =3.886$ ----------------2

Divide 2 and 1 we get

$\tan \theta =\frac{3.886}{8.9\cos (75)}$

$\tan \theta =1.687$

$\theta =59.34^{\circ}$

Thus $u\cos (59.34)=8.9\cos (75)$

$u=4.51 m/s$

7 0

3 years ago

A proposed ocean thermal-energy conversion (OTEC) system is a heat engine that would operate between warm water (25 degrees C) a

Sphinxa [80]

Answer:

$\eta=0.067$

Explanation:

Given that

Temperature of warm water ,T₁ = 25 °C

Temperature of cold water ,T₂ = 5 °C

The maximum possible efficiency of any heat is will be same as the efficiency of the Carnot heat engine.Therefore the maximum efficiency of OTEC system is given as follows

$\eta=1-\dfrac{T_2}{T_1}$

T should be Kelvin scale

Now by putting the values

$\eta =1-\dfrac{5+273}{25+273}$

$\eta=0.067$

Therefore the maximum efficiency will be 0.067 or 6.7%.

8 0

3 years ago

At an average speed of 12 m/s , how many kilometers can a cyclist travel in a 10 hour day?

loris [4]

Answer:

432 km = 432000 m

Explanation:

Primeiro, vamos converter m/s para km/h:

12 m/s = (12 . 3,6)km/h = 43,2 km/h

Agora é só descobrir a distancia que ele percorre em 10 h:

s=43,2.10 = 432 km

Aí se você quiser colocar na medida do Sistema Internacional:

5 0

3 years ago