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Ksivusya [100]
3 years ago
10

Two electrons exert a force of repulsion of 1.2 N on each other. How far apart are they? The elementary charge is 1.602 × 10−19

C and Coulomb’s constant is 8.987 × 109 N · m2/C2. Answer in units of m.
Physics
1 answer:
sergejj [24]3 years ago
5 0

The distance between the charges is 13.86 X 10⁴m

<u>Explanation:</u>

Given:

Force, F = 1.2N

Charge, q₁ = 1.602 X 10⁻¹⁹ C

k = 8.987 X 10⁹ Nm²/C²

Distance, d = ?

According to Coulomb's law:

F = k\frac{q_1q_2}{r^2} \\\\

Substituting the value in the formula we get:

1.2 = 8.987X 10^9 X\frac{1.602 X 10^-^1^9 X 1.602 X 10^1^9}{r^2} \\\\1.2 = \frac{23.06 X 10^9}{r^2} \\\\r^2 = 19.22 X 10^9\\\\r = 13.86 X 10^4m

Therefore, the distance between the charges is 13.86 X 10⁴m

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gaining thermal energy in form of heat

Explanation:

When the thermal energy of a matter is increasing, it will directly increase the kinetic energy of the matter.

  • Temperature changes causes the average kinetic energy of molecules to increase or decrease.
  • If the kinetic energies of particles are increasing, the temperature must have been on rise.
  • Increase in temperature causes molecules to start vibrating and moving about.
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8 0
3 years ago
It is the final seconds of an ice hockey game between the Flyers and the Bruins. The Bruins are down by 1 point. With 20 s left
liberstina [14]

Answer:

a

P =0.1094 \ m past the goal post

Yes the Flyers won the match

Explanation:

Generally the distance covered by the pluck during the last 1.25 seconds is mathematically represented as

     D =  ut + \frac{1}{2} * a * t^2

=>  D =30  * 1.25 + \frac{1}{2} * (-0.5) * (1.25)^2

=>   D =37.1094 \ m

Generally the position of the puck when the game clock reaches zero is mathematically represented as

     P = 37.1094 -37

       P =0.1094 \ m past the goal post

Given that the Bruins where one point down and Flyers scored another goal  it means that the flyer are now two point up hence they won the match

6 0
3 years ago
If a car change the velocity from 36M/S to 28M/S with an acceleration of -2.0 M/S then how much time does it take for the vehicl
leonid [27]

The time it will take if a car change the velocity from 36m/s to 28m/s with an acceleration of -2.0m/s² is 4s.

<h3>How to calculate deceleration?</h3>

Deceleration is the amount by which a speed or velocity decreases (and so a scalar quantity or a vector quantity).

The deceleration of a body can be calculated using the following formula:

-a = (v - u)/t

Where;

  • -a = deceleration
  • v = final velocity
  • u = initial velocity
  • t = time in seconds

-2 = (28 - 36)/t

-2t = -8

t = 4s

Therefore, the time it will take if a car change the velocity from 36m/s to 28m/s with an acceleration of -2.0m/s² is 4s.

Learn more about deceleration at: brainly.com/question/4403243

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6 0
2 years ago
Mr. Stephenson drives his car from Dallas to Town X, a distance of 437 km. The trip takes 7.27 hours. What is the average speed
klasskru [66]

Average speed = (distance covered) / (time to cover the distance).

Distance covered = 437 km = 437,000 meters

Time to cover the distance = (7.27 hrs) x (3600 sec/hr) = 26,172 seconds

Average speed = (437,000 meters) / (26,172 seconds)

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8 0
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1. A student practicing for a track meet ran 263 m in 30 sec. What was her average speed?
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