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V125BC [204]
3 years ago
14

A. StartRoot StartFraction 2 (2) (3) (3) (a) (a) (a) (a) (a) (a) (a) (a) Over 3 (3) (5) (5) (a) (a) EndFraction EndRoot

Mathematics
1 answer:
Aleks04 [339]3 years ago
5 0

Option A. StartRoot StartFraction 2 (2) (3) (3) (a) (a) (a) (a) (a) (a) (a) (a) Over 3 (3) (5) (5) (a) (a) EndFraction EndRoot

Step-by-step explanation:

From all the five options, we need to find the expression which is equivalent to \sqrt{\frac{36 a^{8}}{225 a^{2}}}

Option A: "StartRoot StartFraction 2 (2) (3) (3) (a) (a) (a) (a) (a) (a) (a) (a) Over 3 (3) (5) (5) (a) (a) EndFraction EndRoot" which can be written as

\sqrt{\frac{2(2)(2)(3)(3)\left(a^{8}\right)}{3(3)(5)(5)\left(a^{2}\right)}}=\sqrt{\frac{36 a^{8}}{225 a^{2}}}

Hence, Option A is the correct answer.

Option B: "StartRoot StartFraction 4 a Superscript 6 Baseline Over 25 EndFraction EndRoot" which can be written as

\sqrt{\frac{4a^{6} }{25} } which is not equivalent to \sqrt{\frac{36 a^{8}}{225 a^{2}}}

Hence, Option B is not the correct answer.

Option C: "StartFraction 5 Over 25 EndFraction StartRoot StartFraction a Superscript 8 Over a squared EndFraction EndRoot" which can be written as

\frac{5}{25} \sqrt \frac{a^{8} }{a^{2} } which is not equivalent to \sqrt{\frac{36 a^{8}}{225 a^{2}}}

Hence, Option C is not the correct answer.

Option D: "StartFraction 6 Over 15 EndFraction a Superscript 4" which can be written as

\frac{6}{15} a^{4} which is not equivalent to \sqrt{\frac{36 a^{8}}{225 a^{2}}}

Hence, Option D is not the correct answer.

Option E: "Two-fifths a cubed" which can be written as

\frac{2}{5} a^{3} which is not equivalent to \sqrt{\frac{36 a^{8}}{225 a^{2}}}

Hence, Option E is not the correct answer.

Hence, the correct option is A.

Thus, the expression is equivalent to StartRoot StartFraction 2 (2) (3) (3) (a) (a) (a) (a) (a) (a) (a) (a) Over 3 (3) (5) (5) (a) (a) EndFraction EndRoot.

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